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solniwko [45]
3 years ago
5

________ allows the computer to get its configuration information from the network instead of the network administrator providin

g the configuration information to the computer. It provides a computer with an IP address, subnet mask, and other essential communication information, simplifying the network administrator's job.
Computers and Technology
1 answer:
Lina20 [59]3 years ago
5 0

Answer:

DHCP (Dynamic Host Configuration Protocol)

Explanation:

DHCP is a network protocol that allows network administrators to automatically configure communication information for a network device. The DHCP will, among other things;

i. provide and assign IP addresses to network devices

ii. assign default gateways, DNS information and subnet mask to network devices.

These will reduce the tasks of the network administrator and also provide reliable configuration by reducing errors that are associated with manual configuration of these communication information.

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3 years ago
You can use this area to create your resume.
Svetach [21]

Answer:

what area?

Explanation:

if you need help creating a resume lmk :)

all you really need is

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3 0
3 years ago
When you collaborate or meet with a person or group online, it is called
const2013 [10]

When you collaborate or meet with a person or group online, it is called

cloud computing

social networking

text messaging

web conferencing

Answer:

Cloud computing

Explanation:

Cloud computing is simply defined as the usage of computer resources or networks to communicate with a person or persons over the internet.

This has to do with the exchange of ideas or information between two or more parties over the internet and this can be achieved by using a service such as an email to collaborate, meet or discuss with a person or group online.

4 0
4 years ago
Read 2 more answers
Fwee Pwoints Fwor You! :3
Fittoniya [83]

Answer:

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8 0
3 years ago
Read 2 more answers
Implement a Breadth-First Search of the people in the network who are reachable from person id 3980. You can implement BFS with
Gnoma [55]

Answer:

Check the explanation

Explanation:

import java.io.File;

import java.io.FileNotFoundException;

import java.util.LinkedList;

import java.util.Scanner;

import static org.junit.Assert.assertEquals;

/**

* CS146 Assignment 3 Node class This class is used for undirected graphs

* represented as adjacency lists The areFriends() method checks if two people

* are friends by checking if an edge exists between the two

*

*/

public class NetworkAdjList {

   // Initialize array with max number of vertices taken from SNAP

   static int max_num_vertices = 88234;

   static LinkedList<Integer>[] adjacencyList = new LinkedList[max_num_vertices];

   public static void createAdjacencyList() {

       // Initialize array elements

       for (int j = 0; j < max_num_vertices; j++) {

           adjacencyList[j] = new LinkedList<Integer>();

       }

       // Get file path of the 3980.edges file

       String filePath = "C:\\Users\\shahd\\Documents\\CS146\\Assignment 3\\Question 3\\Question3\\src\\a3\\3980.edges";

       File f = new File(filePath);

       // Use Scanner to read edges from the file and put it into adjacency list

       int a;

       int b;

       try {

           Scanner fileIn = new Scanner(f);

           while (fileIn.hasNext()) {

               a = fileIn.nextInt();

               b = fileIn.nextInt();

               adjacencyList[a].add(b);

               adjacencyList[b].add(a); // We need to add the edges both ways

           }

       } catch (FileNotFoundException e) {

           e.printStackTrace();

       }

   }

   public static boolean areFriends(int A, int B) {

       // If the adjacency list contains (A, B) edge, then return true, else false

       if (adjacencyList[A].contains(B)) {

           return true;

       } else {

           return false;

       }

   }

  private static void bfsHelper(boolean visited[], int currentNode, int dis, int sourceNode) {

       dis++;

       if(!visited[currentNode]) {

           visited[currentNode] = true;

           

           for(int neighbor: adjacencyList[currentNode]) {

               System.out.println(neighbor + " is at a distance of " + dis + " from " + sourceNode);

               bfsHelper(visited, neighbor, dis++, sourceNode);

           }

       }

   }

   public static void BFStraversal(int start) {

       boolean visited[] = new boolean[max_num_vertices];

       bfsHelper(visited, start, 0, start);

   }

   public static void main(String[] args) {

       /**

        * These test cases assume the file 3980.edges was used

        */

       createAdjacencyList();

       System.out.println("Testing...");

       assertEquals(areFriends(4038, 4014), true);

       System.out.println("1 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(3982, 4037), true);

       System.out.println("2 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(4030, 4017), true);

       System.out.println("3 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(4030, 1), false);

       System.out.println("4 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(1, 4030), false);

       System.out.println("5 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(4003, 3980), true);

       System.out.println("6 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(3985, 4038), false);

       System.out.println("7 of 7");

       System.out.println("Success!");

   }

}

**************************************************

8 0
3 years ago
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