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3 years ago

Find all the real fourth roots of 0.0001.

1 answer:

6 0

4th root is even so there can be negative solutions.
0.0001
0.001 * 0.1
0.01 * 0.1 * 0.1
0.1 * 0.1 *0.1 * 0.1

4th root (0.0001) = 0.1 or -0.1

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On the checkerboard, 4/10 of the pieces left are red. What fraction of the pieces left are black? Write the equation.

Alexeev081 [22]

Answer:

The fraction of black pieces left is $\frac{6}{10}$

Step-by-step explanation:

Given as :

On the checkerboard , The fraction of red pieces left = $\frac{4}{10}$

Let The fraction of black pieces left = x

So, The fraction of black pieces left = x = 1 - $\frac{4}{10}$

Or, x = $\frac{10-4}{10}$

Or, x = $\frac{6}{10}$

Hence The fraction of black pieces left is $\frac{6}{10}$ Answer

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3 years ago

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MrRa [10]

Answer:

Step-by-step explanation:

The centroid of a triangle is the intersection of the three medians of the triangle (each median connecting a vertex with the midpoint of the opposite side).

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3 years ago

A<br> What is the product of 7 square root of 2 and 6 square root of 6 in simplest radical form?

ivolga24 [154]

Answer: 84/3

Step-by-step explanation:

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2 years ago

Worth 50 points!I need help plz!

juin [17]

Explanation/Answer:

Total: 4 + 6 + 5 + 7 = 22

Green: 6 + 7 = 13

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3 years ago

Which of the following is equivalent to logb sqrt 57/74

Artemon [7]

Answer:

$\log _b\left(\sqrt{\frac{57}{74}}\right)$ is equivalent to $\frac{1}{2}\left(\log \:_b\left(57\right)-\log \:_b\left(74\right)\right)$ .

Hence, option 'c' is true.

Step-by-step explanation:

Given the expression

$\log _b\left(\sqrt{\frac{57}{74}}\right)$

Rewrite as

$=\log _b\left(\left(\frac{57}{74}\right)^{\frac{1}{2}}\right)$

$\mathrm{Apply\:log\:rule\:}\log _a\left(x^b\right)=b\cdot \log _a\left(x\right),\:\quad \mathrm{\:assuming\:}x\:\ge \:0$

$=\frac{1}{2}\log _b\left(\frac{57}{74}\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _c\left(\frac{a}{b}\right)=\log _c\left(a\right)-\log _c\left(b\right)$

$=\frac{1}{2}\left(\log _b\left(57\right)-\log _b\left(74\right)\right)$ ∵ $\log _b\left(\frac{57}{74}\right)=\log _b\left(57\right)-\log _b\left(74\right)$

Therefore,

$\log _b\left(\sqrt{\frac{57}{74}}\right)$ is equivalent to $\frac{1}{2}\left(\log \:_b\left(57\right)-\log \:_b\left(74\right)\right)$ .

Hence, option 'c' is true.

3 0

3 years ago