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Furkat [3]
3 years ago
5

Round the number 586.356

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0
The answer I believe would be 900.460
Gemiola [76]3 years ago
3 0

Answer:

the answer is 5134681729739181

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Kevin is making a picture frame. He has a piece of trim that is 4 feet long. How many 14-inch long piece can kevin cut from the
Alex777 [14]
First, convert 4 feet into inches - 48 inches. Then, divide 48 by 14 to get 3.43, so he can have 3 14-inch long pieces. To get the left over out of a foot, take 14 x 3 to get 42, then subtract 42 from your original 48 inches to get 6 inches left, which is half of a foot. 
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Read 2 more answers
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

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4200= 4.2 km so
4200 + 325= 4525 meters
jason ran 4525 meters
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Unit 2 Functions Classwork - Homework Day 5 Piecewise Functions
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