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BabaBlast [244]
3 years ago
13

What are the value of x in the equation x^2+4-1 =0

Mathematics
2 answers:
melomori [17]3 years ago
5 0

Answer:

x = ±sqrt(3) i

Step-by-step explanation:

x^2+4-1 =0

Combine like terms

x^2 +3 = 0

Subtract 3 from each side

x^2 +3-3 = 0-3

x^2 = -3

Take the square root of each side

sqrt(x^2) = sqrt(-3)

x = ±sqrt(3) sqrt(-1)

x = ±sqrt(3) i

andrew-mc [135]3 years ago
5 0

Answer:

x = √3 Or 1.73

Step-by-step explanation:

x² + 4 - 1 = 0

combine like terms

x ² + 3 = 0

subtract 3 from both side

x ² + 3 - 3 = 3

x ² = 3

Take square root of both side

√x² = √ 3

x = √3

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