Area shaded = Area big circle- Area of small circle;
200 pi= pi•(2x)^2 -pi•6^2;
200pi= pi•4x^2 -pi•36;
200pi=pi•4(x^2 -9) divide both sides by 4pi;
50=x^2 -9; So x=sqrt(59)~7.68cm
5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
Answer:
y= 3/5x+ 6.2
Step-by-step explanation:
the slope is change in y over change in x.
-4-(-1) divided by 3-8 will be -3/-5 = 3/5
For the y-intercept, plug in x and y values. I will use (3,8).
8= 3/5(3)+b
8= 9/5+b
(subtract 9/5 from both sides)= 6 and 1/5 or 6.2 as a decimal.
Answer:
E) 1 and 2
Step-by-step explanation:
We are given that there are two integers (s and t) and they are factors of another integer (n). For example if s = 3 and t = 2, we can have n = 6.
Thus:
n^(st) = 6^(2*3) = 6^6 = (2^6)(3^6)
For the first condition: s^t = 3^2 is a factor of (2^6)(3^6)
For the second condition: (st)^2 = (3*2)^2 = 6^2 is a factor of 6^6
For the third condition: s+t = 3+2 = 5 is not a factor of 6^6 or (2^6)(3^6)
Therefore, only 1 and 2 are factors of n^(st)
