1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elixir [45]
3 years ago
13

Please help!!!!! Geometry! (Will give Brainliest)

Mathematics
1 answer:
dezoksy [38]3 years ago
7 0

Answer:

Side N: 20

Equation: 5 × 4 = 20

Step-by-step explanation:

Look at the other sides, and try to find a "pattern". Just by looking at the bottoms of the triangles, I saw 4 on BC and 16 on FG. I know that 4 times 4 equals 16, so that could be and option.

Now look at the left side. AB has a length of 3, and EF has a length of 12. I know that 3 times 4 is 12. Both times, there was an increase of 4 between the sides of the triangles.

Now, let's apply this to the last side. 5 times 4 is 20. So, the last side would be 20 on triangle EFG, and the equation would be 5 × 4 = 20.

You might be interested in
If [infinity] cn8n n = 0 is convergent, can we conclude that each of the following series is convergent? (a) [infinity] cn(−3)n
pashok25 [27]

Answer:

a) we know that this is convergent.

b) we know that this might not converge.

Step-by-step explanation:

Given the \sum^\infty_{n=0}C_n8^n is convergent

Therefore,

(a)  \sum^\infty_{n=0}C_n(-3)^n The power series \sum C_nx^n has radius of convergence at least as big as 8. So we definitely know it converges for all x satisfying -8<x≤8. In particular for x = -3

∴ \sum^\infty_{n=0}C_n(-3)^n  is convergent.

(b) \sum^\infty_{n=0}C_n(-8)^n -8 could be right on the edge of the interval of convergence, and so might not converge

8 0
3 years ago
A student wants to construct the inscribed circle of a triangle. What is the first step he/she should take?
pantera1 [17]

The <em>correct answer</em> is:


d) Construct the angle bisector of each angle in the triangle


Explanation:


The incenter, or center of an inscribed circle, is the point where the angle bisectors of a triangle intersect. This means the first thing we will need to construct is the bisector of each angle of the triangle.

8 0
3 years ago
Read 2 more answers
Find the area of the following figure. get brainliest if correct&lt;3
Alexus [3.1K]

Answer:

312

Step-by-step explanation:

because when you add the triangles and rectangles together you get 312

7 0
2 years ago
Read 2 more answers
A math class has 3 girls and 9 boys in the seventh grade and 7 girls and 3 boys in the eighth grade. The teacher randomly select
vladimir1956 [14]

Answer:

7/40

Step-by-step explanation:

There are 3 girls+9 boys = 12 students in the 7th grade

P (girl in 7th grade) = girls/ total

                                = 3/12 = 1/4

There are 7 girls+3 boys = 10 students in the 8th grade

P (girl in 8th grade) = girls/ total

                                = 7/10

P(7th grade girl, 8th grade girl) = 1/4 * 7/10 = 7/40

8 0
3 years ago
1. Fill in the blanks:
Rom4ik [11]

the answer from, (a to e) is 10

7 0
1 year ago
Read 2 more answers
Other questions:
  • 150 seconds is &gt;, &lt;, or = 3 minutes
    10·2 answers
  • Sneha works two part-time jobs. One job is at a tutoring company that pays $19 an hour, and the other is pumping gas for $11.50
    6·1 answer
  • You need 150g of flour for 12 cakes, how much flour do you need for 30 cakes?
    8·2 answers
  • Given the following perfect square trinomial, fill in the missing term.<br><br> x^2 - 6x + __
    8·1 answer
  • Identify two factors that have a product of 1 7/8.<br><br><br> Will give Brainliest
    11·2 answers
  • Please answer PLEASE
    8·2 answers
  • Find the LCD. 9, 12 The LCD is<br><br><br><br> please help and quick!!
    15·2 answers
  • Pls explain. will mark brainliest ​
    5·1 answer
  • 1. Which of the following is a true statement?
    7·2 answers
  • Having trouble solving this problem from my ACT prep bookIt is trigonometry
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!