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3 years ago

I need help please! Thank you

Mathematics

1 answer:

Debora [2.8K]3 years ago

7 0

Answer:

We also know that If two angles are complementary then their sum is equal to 90°. So, two angles ∠1 & ∠2 are complementary.

Step-by-step explanation:

As BA is perpendicular to BC. So, angle ∠ABC is 90°.

We also know that If two angles are complementary then their sum is equal to 90°. As ∠ABC is the sum of the ∠1 & ∠2. In other words, ∠1 & ∠2 are complementary. So, two angles ∠1 & ∠2 are complementary.

Lets prove this.

Given: BA ⊥ BC

Prove: ∠1 & ∠2 are complementary.

Statement Reasons

1. ∠1 & ∠2 are complementary 1. Given

2. ∠1 + ∠2 = 90° 2. Def. of complementary angles

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Hayley so 20 tickets to the school play for total of $225. Early bird tickets were $10 regular priced tickets are $15. Wright an

alexandr402 [8]

System of Equations

For the problem to solve we'll use the following variables:

x = number of the early bird tickets sold

y = number of the regular tickets sold

Haley sold a total of 20 tickets, thus:

x + y = 20 [1]

Early bird tickets cost $10 and regular tickets cost $15, thus the total money collected is:

10x + 15y = 225

Dividing by 5:

2x + 3y = 45 [2]

We have to solve the system of equations [1] and [2].

Multiply [1] by -2:

-2x - 2y = -40 [3]

Add [3] to [2]:

-2x - 2y +2x + 3y = -40 + 45

Simplifying:

y = 5

Substituting in [1]:

x + 5 = 20

Subtracting 5:

x = 20 - 5

x = 15

Solution: Hayley sold 15 early bird tickets and 5 regular-priced tickets

The order pair solution is (15,5)

5 0

1 year ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

40% of the children in a sports club play badminton. 25% of the children who play badminton also play squash. There are 11 child

Keith_Richards [23]

Answer:

There are 110 children total in the sports club

Step-by-step explanation:

To get this answer, its actually easier than it seems. You might need a calculator however.

First you start with the 11 children who play both badminton and squash, then, you divide that by 0.25 (25%) to get 44.

Next you take 44 and divide it by 0.4 (40%) to get 110.

And there you go! If you want to make sure you got it right simply start with 110 and multiply it by 0.4 then multiply the number/decimal you get by 0.25. You should get 11 to confirm your answer :)

6 0

4 years ago

Given the function f(x) graphed on the coordinate plane 15

den301095 [7]

Answer:

Step-by-step explanation:

5 0

3 years ago

Tickets for a certain show cost $17, $21, or, for VIP seats, $40. If ten times as many $17 tickets were sold as VIP tic

lawyer [7]

Answer:

Tickets sold:

VIP $=126$

$17 tickets $=1,260$

$21 tickets $=9\cdot 126+57=1,191$

Step-by-step explanation:

Let x be the number of VIP tickets.

If ten times as many $17 tickets were sold as VIP tickets, then the number of $17 tickets is $10x.$

If the number of $17 tickets sold was 57 more than the sum of the number of $21 tickets and VIP tickets, then $10x+57=x+y$ and the number y of $21 tickets is $9x+57.$