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3 years ago

I need help please! Thank you

Mathematics

1 answer:

Debora [2.8K]3 years ago

7 0

Answer:

We also know that If two angles are complementary then their sum is equal to 90°. So, two angles ∠1 & ∠2 are complementary.

Step-by-step explanation:

As BA is perpendicular to BC. So, angle ∠ABC is 90°.

We also know that If two angles are complementary then their sum is equal to 90°. As ∠ABC is the sum of the ∠1 & ∠2. In other words, ∠1 & ∠2 are complementary. So, two angles ∠1 & ∠2 are complementary.

Lets prove this.

Given: BA ⊥ BC

Prove: ∠1 & ∠2 are complementary.

Statement Reasons

1. ∠1 & ∠2 are complementary 1. Given

2. ∠1 + ∠2 = 90° 2. Def. of complementary angles

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Help quick!! I'll mark your answer as the brainliest if it's correct! Identify the function shown in this graph.

sattari [20]

Answer:

Step-by-step explanation:

We see that the y-intercept is 3. So it is either A of B.

Plug in the point that is on the line (1, -2), we see that the point works for C.

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2 years ago

_Izzy wants to paint three walls in her family room. Two walls are 13

stiks02 [169]

The total area would be the combined area of all three

Let’s knock out the first 2

4.5 * 13 = 58.5 * 2 = 117

Now the last

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2 years ago

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3^2 • 3^-8 • 3^0<br> i need help with this asap

pantera1 [17]

Steps to solve:

3^2 • 3^-8 • 3^0

~Apple exponent rule [ a^b * a^c = a^b+c ]

3^2-8+0

~Simplify

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2 years ago

Read 2 more answers

Line M passes through point (3,1) and is perpendicular to the line of the equation y=3x+4. Which equation describes the graph of

zheka24 [161]

Answer:

y = -1/3x + 2

Step-by-step explanation:

The gradient of the given line is 3 because (y = mx +c where m is the gradient)

Therefore, to find the gradient of the perpendicular line (at 90 degrees), you need to find the negative reciprocal.

The negative reciprocal of 3 is -1/3 because imagine if 3 = 3/1, to get the reciprocal, you flip it, and to get the negative, you just flip the sign.

Now we know that Line M is y = -1/3x + c, we need to find the y-intercept.

To do this, just input the point (3,1) into y = -1/3x + c, to get c. This is because we know (3,1) is on the line from the question.

So it would be 1 = (-1/3 x 3) +c

Which would be 1 = -1 +c

And so c = 2

Put everything together and you get y = -1/3x + 2

8 0

3 years ago

PLEASE HELP!!!!!

Zielflug [23.3K]

Question #1

Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.

Part B:
$\sf Slope = \frac{27-5}{1-0} = \frac{22}{1} = \boxed{22}$
The slope is 22.

Part C:
y = mx + b
y = 22x + 5

We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10

The domain is 10.

Question #2

Part A:

(2,255)
(5,480)

Standard form is Ax + By = C

$\sf Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{480-225}{5-2} = \frac{255}{3} = \boxed{85}$

Let's plug this into this form first:
$y - y_1 = m(x-x_1)\\\\y -225 = 85(x-2)\\\\y - 225 = 85x - 170\\\\y = 85x + 55$

Now, let's make it into Standard Form.
$y = 85x + 55\\\\y - 85x + 55\\\\ -85x + y = 55\\\\ -1(-85x +y) = -1(55)\\\\\boxed{85x - y = -55}$
What, which is in the box, is your final answer. :)

Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
$\boxed{f(x) = 85x + 55}$

Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)

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3 years ago