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IrinaK [193]
3 years ago
7

The length of a​ standard-sized rectangular rug is 2 feet longer than the width. Let x be the width. Which of the following quad

ratic inequalities indicates that the area of the rug is no less than 80 square feet?

Mathematics
1 answer:
ipn [44]3 years ago
7 0

Answer:

B

Step-by-step explanation:

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11 units long.  When something is rotated it does not change its shape/length, only when it is dilated.
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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x
Andrei [34K]

Answer:

\large\boxed{A.\ (x+6)^2+(y+10)^2=20}

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-6, -10) and (-8, -6):

r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}

Finally we have

(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20

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3 years ago
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A man bought a bicycle for $400 and sold it at a loss of 35%. How much money did he lose?
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Additionally, if you wanted to know what exactly he sold it for, you would simply subtract 140 from 400. Which would be $260.

So, he bought the bike for $400, but when he resold it, he lost $140 of that pay. Basically, he resold the bike for $260. 

I hope this helps! :) Let me know if you need help with anything else!
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G(x)=1/2(x-3)+1 find the inverse
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g(x)=\dfrac{1}{2}(x-3)+1\\\\y=\dfrac{1}{2}(x-3)+1\\\\\text{replace x with y and y with x}\\\\x=\dfrac{1}{2}(y-3)+1\\\\\text{solve for y}\\\\\dfrac{1}{2}(y-3)+1=x\ \ \ \ |-1\\\\\dfrac{1}{2}(y-3)=x-1\ \ \ \ |\cdot2\\\\y-3=2x-2\ \ \ \ |+3\\\\y=2x+1\\\\Answer:\ \boxed{g^{-1}(x)=2x+1}

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Step-by-step explanation:

Area of circle =πr²

  • 3×5×5
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<h2>stay safe healthy and happy.</h2>
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