10 + f = 10
-10 -10
f = 10 - 10
f = 0.
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
brainly.com/question/25970931
#SPJ1
Wouldn't it be 150 cubic centimeters? Since it has the same area of base and height, it would be the same prism.
we know that
1 ft--------> is equals to 12 in
the ramp is 12 inches tall----------> 1 ft tall
A ramp measures------------------> 6 ft long
applying the Pythagorean theorem
c²=a²+b²
where
c-----> 6 ft long
a----> horizontal distance
b-----> 1 ft tall
a²=c²-b²------> a²=6²-1²-----> a²=35------> a=√35------> a=5.92 ft
the answer is
5.92 ft
