All categories

2 years ago

A line passes through the origin and the point (3,5). What is the slope of the line?

1 answer:

4 0

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 0}}\quad ,&{{ 0}})\quad 
% (c,d)
&({{ 3}}\quad ,&{{ 5}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{5-0}{3-0}$

You might be interested in

Please answer asap!!!

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve the triangle.

saw5 [17]

Answer:

Step-by-step explanation:

because c is shorter than a we know C is a smaller angle than A

so the first choice is out.

use the law of cosines to find b

$b^{2}$ = $a^{2} +c^{2} -2*a*c*cos(B)$

$b^{2}$ =1681+400-1326.787871

$b^{2}$ = 754.21219

b= $\sqrt{754.21219}$

b= 27.46292

so the last choice looks good

5 0

2 years ago

Graph the line with the equation y=-x-5y=−x−5.

AVprozaik [17]

Answer:

Just getting points i hope u find the answer tho :))

Step-by-step explanation:

5 0

2 years ago

Please give the answer. what is 44x65

timofeeve [1]

44x65=2860 is the answer

7 0

3 years ago

Read 2 more answers

Help me please

kari74 [83]

Answer:

$\frac{ \cos(80) }{ \sin(10) } + \frac{ \sin(20) }{ \cos(70) } = 2 \\ \frac{ \cos(90 - 10) }{ \sin(10) } + \frac{ \sin(20) }{ \cos(9 0 - 20) } = 2 \\ \frac{ \sin(10) }{ \sin(10) } + \frac{ \sin(20) }{ \sin(20) } = 2 \\ 1 + 1 = 2 \\ 2 = 2 \\ \\ \frac{ \cot(40) }{ \tan(50) } + \frac{ \cos(65) }{ \sin(115) } = 2 \\ \frac{ \cot(90 - 50) }{ \tan(50) } + \frac{ \cos(65) }{ \sin(90 + 65) } = 2 \\ \frac{ \tan(50) }{ \tan(50) } + \frac{ \cos(65) }{ \cos(65) } = 2 \\ 1 + 1 \\ = 2$

6 0

2 years ago