Option C
The distance of a spin of one full rotation is 31.4 feet
<em><u>Solution:</u></em>
Given that,
A circular merry-go-round has a radius of 5 feet
Radius = 5 feet
We have to find the distance of spin for one full rotation
Distance covered in 1 full of rotation is equal to circumference of circle
<em><u>The circumference of circle is given as:</u></em>
Where "r" is the radius
Thus the distance of a spin of one full rotation is 31.4 feet
Answer:
A. 63 degrees
Step-by-step explanation:
Complementary angles are angles that add up to 90 degrees. You can make an equation to solve for angle N:
27 + x = 90
rearrange the equation:
90 - 27 = x
63 = x
Answer:
<u>Let's verify is the corresponding sides have same ratio:</u>
- ΔABC, sides: 6, 9, 11
- ΔXYZ, sides: 21, 31.5, 38.5
<u>Ratios:</u>
- 6/21 = 2/7 (divide by 3)
- 9/31.5 = 2/ 7 (divide by 4.5)
- 11/38.5 = 2/7 (divide by 5.5)
The ratios are same, so the triangles <u>are similar</u>
- Yes, the sides are all proportional
The scale factor (ΔABC to ΔXYZ) is <u>2/7</u> (or ΔXYZ to ΔABC is 7/2 = <u>3.5</u>)
Answer:
4
Step-by-step explanation:
![\huge \sqrt[4]{256} = \sqrt[4]{ {4}^{4} } = 4](https://tex.z-dn.net/?f=%20%5Chuge%20%5Csqrt%5B4%5D%7B256%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B%20%7B4%7D%5E%7B4%7D%20%7D%20%3D%204%20%20)
Answer:
20
Step-by-step explanation:
I must assume that you meant
p^2 + 7p
---------------
3
If p = 5, then this expression becomes:
5^2 + 7(5) 25 + 35
------------------ = -------------- = 60/3 = 20
3 3
