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Semenov [28]
3 years ago
9

C) - 6 X-3 = ? What is the answer?

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
5 0

Answer:

- 6 X-3 = 18

nlexa [21]3 years ago
3 0
Use the app Photomath, the answer is always correct and it’s positive 18
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Find the perimeter and area of a rectangle with a width of 2 feet and a length 3 times as long.
rusak2 [61]

Answer:

Length = Width * 3

Width = 2 ft

Length = 2 ft * 3 = 6 ft

Perimeter = (L * 2) + (W * 2)

P = 16 ft

Area = L * W = 12 square feet

5 0
3 years ago
Read 2 more answers
Find the value of N in the question
iris [78.8K]
N = 1/3 -0
n = 1/3

answer
n = 1/3
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3 years ago
An equation is shown.
lubasha [3.4K]
<span>2(a+b)=c
2a + 2b = c
2b = c - 2a
  b = (c - 2a)/a

answer
</span><span>D. b = (c−2a)/2 ; distribute 2 to get 2a+2b, subtract 2a, then divide by 2.</span>
3 0
3 years ago
Help me! I am confused
ArbitrLikvidat [17]
We know the workers can unpack 48 books in 2 minutes, so how many minutes for 200?

\bf \begin{array}{ccll}&#10;books&minutes\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;48&2\\&#10;200&m&#10;\end{array}\implies \cfrac{48}{200}=\cfrac{2}{m}\implies m=\cfrac{200\cdot 2}{48}&#10;\\\\\\&#10;m=\cfrac{25}{3}\implies m=8\frac{1}{3}\impliedby \textit{8 minutes and 20 seconds}
3 0
4 years ago
Please Help?
posledela

Answer:

See explanation

Step-by-step explanation:

The place to begin in attempting to solve a quadratic equation is to try to factorize it. If it can not be factorized, then look at the side of equation that contains the variable (x,b,m,n and so on). If that side is a perfect square, try to take square root of both sides.

Also, if the coefficient of the squared term in the equation is 1 and the coefficient of the middle term bearing the variable is an even number, then you can attempt to use completing the square method. Formula method can be adopted as a last resort.

x^2 -4x + 4 =0 can be solved by factorization

X(x-2) - 2(x-2) =0

Hence;

(x-2) (x-2) =0

x= 2 (twice)

(2x-2)^2 = 4 can be solved by taking square root

√[(2x-2)^2] = √4

2x-2 = 2

x= ±2

x^2 + 6x - 11 = 0 can be solved by completing the square

(x + 3)^2 = 11 + 3^2

(x + 3)^2 = 20 taking square root of both sides

x + 3 = ±√20

x + 3 = ±2√5

x= -3 ±2√5

2x^2 - x + 5 = 0 can be solved by formula method

Using

x= -b±√b^2 - 4ac/2a

a= 2, b = -1, c= 5

x= 1 ± √1 - 40/4

x= 1 ± √-39/4

x= 1 ± 39i/4

5 0
3 years ago
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