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wlad13 [49]
4 years ago
12

6 is greater than or equal to x and -2 is less than x

Mathematics
1 answer:
Kryger [21]4 years ago
4 0
X is any number between -1 and 6.

Numbers x can be:
x=-1
x=0
x=1
x=2
x=3
x=4
x=5
x=6
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2(4x - 3) - 8 = 4 +2x
Lubov Fominskaja [6]
The variable x is equal to 3
5 0
3 years ago
Read 2 more answers
Suppose 3/4 is a root of a polynomial equation. what does this tell us about the leading coefficient and the constant term in th
snow_tiger [21]

Answer:

Nothing new about leading coefficient. Definition says it can't be zero. It can always be made equal to one by dividing through.

Constant term cannot be zero unless a root is zero.


Step-by-step explanation:

x-3/4 = 0 has root 3/4 constant term -3/4


(x-3/4)(x-b) = 0 has roots 3/4 and b, constant term 3b/4 which is zero only if b is zero.


(x-3/4)(x-b)(x-c) = 0 has roots 3/4, b, c, constant term -3bc/4 which is zero only if b or c is zero.


Etc. ...

5 0
3 years ago
Please help I will mark as brainliest
MrMuchimi

Answer:

no

Step-by-step explanation:

3 0
4 years ago
Riley has collected surveys for her final thesis project. One one question, 46.1% of respondents said that conditions were impro
ira [324]

Answer:

The maximum value of the confidence interval for this set of survey results is 51.73%.

Step-by-step explanation:

A confidence interval has two bounds, a lower bound and an upper bound.

These bounds depend on the sample proportion and on the margin of error.

The lower bound is the sample proportion subtracted by the margin of error.

The upper bound is the margin of error added to the sample proportion.

In this question:

Sample proportion: 46.1%

Margin of error: 5.63%.

Maximum value is the upper bound:

46.1+5.63 = 51.73

The maximum value of the confidence interval for this set of survey results is 51.73%.

5 0
4 years ago
Please answer both with work,please use a paper and picture, thanks ​
Irina-Kira [14]

Answer:

a.  $ \frac{\textbf{17}}{\textbf{4}} $

b.  $ \frac{\textbf{3}}{\textbf{8}} $

Step-by-step explanation:

a. $ \textbf{3} \hspace{1mm} \textbf{+} \hspace{1mm} \textbf{1}\frac{\textbf{1}}{\textbf{4}} $

A mixed fraction of the form $ a\frac{x}{y} = a + \frac{x}{y} $

$ \therefore 3 + 1\frac{1}{4} = 3 + 1 + \frac{1}{4} $

$ = 4 + \frac{1}{4} $

$ = \frac{\textbf{17}}{\textbf{4}} $

b. $ \textbf{2} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{1}\frac{\textbf{5}}{\textbf{8}} $

A mixed fraction of the form $ -c\frac{a}{b} = - c - \frac{a}{b} $

$ \therefore 2 - 1\frac{5}{8} = 2 - 1 - \frac{5}{8} $

$ = 1 - \frac{5}{8} $

$ = \frac{8 - 5}{8} $

$ = \frac{\textbf{3}}{\textbf{8}} $

Hence, the answer.

8 0
4 years ago
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