Alright, lets get started.
Jim was thinking of a number.
Suppose the number Jim was thinking, is x.
Jim adds 20 to it means number will be = 
And Jim doubles it, means 
Jim gets 99.2 and as per us, he gets 
So, making them equal


Subtracting 40 in both sides



It means the original number is 29.6. : Answer
Hope it will help :)
Answer:

Step-by-step explanation:
Connect points I and K, K and M, M and I.
1. Find the area of triangles IJK, KLM and MNI:

2. Note that

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.
9×2=18. add the tow zeros like this 9×2=18+00=1,800
Answer:
36
Step-by-step explanation:
um here
9 x 4 = 36
hope it helps :D
Multiply 4&8, that makes 32 then add the numerator which is 7. 32+7=39, the improper fraction is 39/8. Hope this helps. If you need more info look online