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Aneli [31]
3 years ago
14

Part A: The average rate of change between the 2nd and 3rd point is Select a Value Part A: The average rate of change between th

e 3rd and 4th point is Select a Value Part B: The average rate of change between the 2nd and 3rd point is Select a Value Part B: The average rate of change between the 4th and 5th point is Select a Value
Mathematics
1 answer:
Fofino [41]3 years ago
7 0

Answer:

Rate = 6

Rate = 10

Rate = 18

Rate = 162

Step-by-step explanation:

Given

See attachment for table

Solving (a): Rate of change between 2nd and 3rd point on A

The rate of change is calculated as:

Rate = \frac{y_2 - y_1}{x_2 - x_1}

In table A, the 2nd and 3rd point is:

(x_1,y_1) =(1,7)

(x_2,y_2) =(2,13)

So, the average rate of change is:

Rate = \frac{13 - 7}{2 - 1}

Rate = \frac{6}{1}

Rate = 6

Solving (b): Rate of change between 3rd and 4th point on A

In table A, the 3rd and 4th point is:

(x_1,y_1) =(2,13)

(x_2,y_2) =(3,23)

So, the average rate of change is:

Rate = \frac{23 - 13}{3 - 2}

Rate = \frac{10}{1}

Rate = 10

Solving (c): Rate of change between 2nd and 3rd point on B

In table B, the 2nd and 3rd point is:

(x_1,y_1) =(2,11)

(x_2,y_2) =(3,29)

So, the average rate of change is:

Rate = \frac{29 - 11}{3 - 2}

Rate = \frac{18}{1}

Rate = 18

Solving (d): Rate of change between 4th and 5th point on B

In table B, the 4th and 5th point is:

(x_1,y_1) =(4,83)

(x_2,y_2) =(5,245)

So, the average rate of change is:

Rate = \frac{245 - 83}{5 - 4}

Rate = \frac{162}{1}

Rate = 162

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If the two buses are 640 miles apart after 5 hours. Then the rate of each bus will be 57 miles per hour and 71 miles per hour.

<h3>What is speed?</h3>

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

Speed = Distance/Time

Two buses leave a station at the same time and travel in opposite directions.

One bus travels 14 miles faster than the other.

Let x be the speed of first bus. Then the speed of the second bus will be (x + 14).

If the two buses are 640 miles apart after 5 hours.

Then the rate of each bus will be

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