Answer:
Claim : men weigh of wild jackalopes is 69.9
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Test statistic = −2.447085
P value = 0.0174
Conclusion :
Fail to Reject the Null hypothesis
Step-by-step explanation:
From the question given :
The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Using calculator :
Sample mean (x) = 66
Sample standard deviation (s) = 12.345
The test statistic t :
(x - μ) / (s/√n)
n = sample size = 60
(66 - 69.9) / (12.345 / √60)
t = −2.447085
P value at α 0.01, df = 59 is 0.0174
Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null
Answer:
There are 64,000 possible codes. Jillian is incorrect, since he added the possible options in each trial, instead of multiplied them(he did 40+40+40 instead of 40*40*40).
Step-by-step explanation:
From 0 to 39, there are 40 numbers.
The code has three values:
V1 - V2 - V3
When we have n trials with m possible options, the total number of opitons is:

In this question:
3 trials(values), with 40 options. So

There are 64,000 possible codes. Jillian is incorrect, since he added the possible options in each trial, instead of multiplied them(he did 40+40+40 instead of 40*40*40).
The first answer is c
42cm(2)
I believe the answer will be 23in
Answer:
50 %
Step-by-step explanation:
From the diagram attached,
Percentage of total students that like watching television = [(WnR)/μ]×100......... Equation 1
The number of students that like watching television and reading (WnR) = 70
The total number of students (μ) = 40+20+70+10
The total number of students (μ) = 140
Substitute these values into equation 1
Percentage of total students that like watching television = (70/140)×100
Percentage of total students that like watching television = 1/2(100)
Percentage of total students that like watching television = 50 %