<h3>
Answer: (m+n)/(mn)</h3>
Work Shown:
Josh:
1 room = m hours
1/m room = 1 hour
Kevin:
1 room = n hours
1/n room = 1 hour
We see that the rates for Josh and Kevin are 1/m and 1/n respectively. This is the amount of a room they paint in one hour. Combine the fractions
1/m + 1/n = n/(mn) + m/(mn) = (n+m)/(mn) = (m+n)/(mn)
The expression (m+n)/(mn) represents how much of the room they get painted in 1 hour. This is if they work together and it assumes neither worker slows the other one down.
Answer: A y=4x^2+1
Step-by-step explanation:According to slope A is the answer
Answer:
c+2c+12=75
c = 21
Steps:
c+2c+12=75
Simplify both sides of the equation.
c+2c+12=75
(c+2c)+(12)=75(Combine Like Terms)
3c+12=75
3c+12=75
Subtract 12 from both sides.
3c+12−12=75−12
3c=63
Divide both sides by 3.
Answer:
Step-by-step explanation:
In the model
Log (salary) = B0 + B1LSAT +B2GPA +B3log(libvol) +B4log(cost)+B5 rank+u
The hypothesis that rank has no effect on log (salary) is H0:B5 = 0. The estimated equation (now with standard errors) is
Log (salary) = 8.34 + .0047 LSAT + .248 GPA + .095 log(libvol)
(0.53) (.0040) (.090) (.033)
+ .038 log(cost) – .0033 rank
(.032) (.0003)
n = 136, R2 = .842.
The t statistic on rank is –11(i.e. 0.0033/0.0003), which is very significant. If rank decreases by 10 (which is a move up for a law school), median starting salary is predicted to increase by about 3.3%.
(ii) LSAT is not statistically significant (t statistic ≈1.18) but GPA is very significance (t statistic ≈2.76). The test for joint significance is moot given that GPA is so significant, but for completeness the F statistic is about 9.95 (with 2 and 130 df) and p-value ≈.0001.
Answer:
Step-by-step explanation:
The answer is B.
Use the sum-product pattern
2+3−3−9
Common factor from the two pairs
2+3−3−9x2+3x−3x−9
(+3)−3(+3)
Rewrite in factored form
(+3)−3(+3)
Solution:
(−3)(+3)
‘Hope it Helps!
