Answer:
1.6, 1 4/5 (1.8), 1.82
Step-by-step explanation:
I think you may have forgotten to attach the actual problem
Answer:

Step-by-step explanation:
Given:
The average cost of a computer in the year 2000 is given as:

The average cost of a computer in the year 2008 is given as:

Now, the difference in average cost between the years 2008 and 2000 can be calculated by subtracting the average cost in 2000 from the average cost in 2008.
Framing in equation form, we get:
Difference in average cost (ΔC) is given as:

Therefore, the difference in the costs for a computer between 2008 and 2000 is 
Step-by-step explanation:
multiply 5x+2y=19 by 3 youll get 15x+6y=57
eliminate y
7x-6y=9
<u>15x+6y=57</u><u> </u> +
22x=66
x=3
substitute x to 5x+2y=19
15+2y=19
2y=4
y=2
To get the answer we have to multiply 25 times 21 7/8. To do that we have to transform 21 7/8 into improper fraction and thn multiply 25 times numerator.


- its the answer