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3 years ago

For equation y=6x^2-9x+22 choose the correct application of the quadratic formula

2 answers:

8 0

You didn't list any choices.

anyway here's the solution solved with the quadratic formula:
a = 6 b=-9 c=22
The solution would be:
x =[--9 +-square root (81 - 4*6*22)] / 12
x = [9 +- square root (81 -528)] / 12
x = [9 +- square root (-447)] / 12
x = .75 (+- 1.7619 i)

slamgirl [31]3 years ago

6 0

I took this test today! The answer is D, x = 9 <u>+</u> √(-9)² - 4(6)(22<u>)</u> ÷ 2(6).

∞Please rate me Brainliest! Have a wonderful day!∞

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27)

Alja [10]

Answer:

A). No triangle.

Step-by-step explanation:

In order to construct a triangle the sum of any 2 sides must be greater than the third side.

Here 5 + 8 ( =13) is less than the 3rd side, which has a length of 15.

3 0

3 years ago

The Jelly Junior High school color is made by mixing red paint with yellow paint. The ratio of red to yellow is 3 to 5. How much

user100 [1]

V/a = 3/5
a = 20
v = ...

3/5 = v/20
5v = 20*3
5v = 60
v = 60/5
v = 12 oz

8 0

4 years ago

-(19-2a^2)-57+4g^2 simplify, and please include step by steps thanks

Katyanochek1 [597]

Answer:

2(-17+a^2+2g^2)

Step-by-step explanation:

step1

3 0

3 years ago

Write the equation of the line that passes through the points (7,-6) and (0,2). Put

Alex

Answer:

$y+6=\frac{-8}{7} (x-7)$

Step-by-step explanation:

To find the slope of the equation use $\frac{y_2-y_1}{x_2-x_1}$ .

So, $\frac{-6-2}{7-0}$ = $\frac{-8}{7}$ . Now we can use our slope and any of the two points to write in point-slope form, which is $y-y_1=m(x-x_1)$ . Using the point (7,-6), the formula will give $y+6=\frac{-8}{7} (x-7)$ .

To check, you can plug in this equation and the points into a calculator to graph. The line passes through both points.

6 0

3 years ago

For X a binomial random variable with n=5 and p=1/4, answer the following

mash [69]

Recall that for $X\sim\mathrm{Bin}(n,p)$ , i.e. a random variable $X$ following a binomial distribution over $n$ trials and with probability parameter $p$ ,

$\mathbb P(X=x)=f_X(x)=\begin{cases}\dbinom nx p^x(1-p)^{n-x}&\text{for }x\in\{0,1,\ldots,n\}\\\\0&\text{otherwise}\end{cases}$

So you have

$\mathbb P(X=2)=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac34\right)^{5-2}=\dfrac{135}{512}\approx0.26$

$\mathbb P(2\le X\le4)=\displaystyle\sum_{x=2}^4\mathbb P(X=x)$
$=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac14\right)^{5-2}+\dbinom52\left(\dfrac14\right)^3\left(1-\dfrac14\right)^{5-3}+\dbinom52\left(\dfrac14\right)^4\left(1-\dfrac14\right)^{5-4}$
$=\dfrac{375}{1024}\approx0.37$

The expected value of $X\sim\mathrm{Bin}(n,p)$ is simply $np$ , while the standard deviation is $\sqrt{np(1-p)}$ . In this case, they are $\dfrac54=1.25$ and $\sqrt{\dfrac{15}{16}}\approx0.97$ , respectively.

7 0

3 years ago