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Shalnov [3]
3 years ago
15

Cole said All prime numbers are odd and all composite numbers are even do you agree with cole?

Mathematics
2 answers:
prisoha [69]3 years ago
4 0
All prime numbers are odd except for the number two. A prime number is defined as any whole number greater than one that has no positive divisors except for one and itself. Since two can only be divided by the numbers one and two, it is prime.       <span>The </span>composite numbers<span> are integers having at least two prime factors, whereas a prime </span>number<span> has a single prime factor (itself), and the unit 1 has no prime factors at </span>all<span>. For example, 10 is </span>composite, as it has two prime factors (2 and 5). 11 is notcomposite<span>, since its only prime factor is itself.</span>
Anit [1.1K]3 years ago
3 0
A prime number is such that it is divisible by only itself and one. ... Two is a prime because it is divisible by only two and one. All the other even numbers are not prime because they are all divisible by two. That leaves only the odd numbers.
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Use the x-intercept method to find all real solutions of the equation. -9x^3-72x^2+36=3x^3+x^2-3x+8
larisa86 [58]

-9x^3-72x^2+36=3x^3+x^2-3x+8                     Add 9x^3 to both sides.

-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8       Add 72x^2 to both sides

36 = 12x^3 +   73x^2 - 3x + 8                           Subtract 36 from both sides.

0 = 12x^3 + 73x^2 - 3x - 28      

It does factor, but it is not very nice.

(x + 6.06)(x - 6.09)(x + 0.632)

If there is any kind of error please report it in a note below.

6 0
3 years ago
8% of what number is 2
sesenic [268]
25 is the number. Hope this helps.
5 0
2 years ago
Does anyone know how to solve this? It’s really starting to stress me out.
bekas [8.4K]

Answer:

π − 12

Step-by-step explanation:

lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

lim(u→0) (sin(π(u + 2)) + 8 − (u + 2)³) / ((u + 2) − 2)

lim(u→0) (sin(πu + 2π) + 8 − (u + 2)³) / u

Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

lim(u→0) (sin(πu) / u) + lim(u→0) (-u² − 6u − 12)

lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

π lim(u→0) (sin(πu) / (πu)) − 12

Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

π − 12

3 0
3 years ago
What is 5% of 20?<br> Please help me
zloy xaker [14]

Answer:

1

Step-by-step explanation:

5% × 20 =

(5 ÷ 100) × 20 =

(5 × 20) ÷ 100 =

100 ÷ 100 =

1

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3 years ago
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