Accenture is a company that was established with the aim of handling electronic waste. They were very much concern about how electronic waste is being disposed and as such they try to create ways to handle it. The e-stewards program was set up with the sole aim of management of electronic waste. its objectives includes;
- Make strategic and better world through well managed recycling solution to all electronic waste (e-waste) issues.
- The program also focus on making sure that electronic waste are been handled properly and they are not dumping of electronic waste in poor countries
- The objective also centers around no export of harmful electronic wastes.
- They also capitalizes on reuse and resale
- They are not only interested in stopping e-waste but to channeled it to repair, republish and re-manufacture
For better understanding, lets explain what E-waste means
- E-Steward objective is centered on managing and handling of electronic waste. It was a project that was birth out of rising concern about electronic waste, especially due to rising concerns that electronic waste generated by rich countries was being shipped off to poor countries.
- Accenture e-steward make sure that electronic waste are well disposed, no more shipping of electronic waste to poor countries and also recycling of electronic waste product.
- E-waste in the above simply means non functional or disposed electronic equipment such as computers, cell phones, television sets, etc.
From the above, we can therefore say that the e-stewards program is concerns about how electronic waste generated by rich countries was being shipped off to poor countries and also the recycling of electronic waste product such as television, computers etc.
Learn more about E-waste from:
brainly.com/question/15391967
Answer:
Start
Input n, 2
Calculate if (n%2==0) then is divisible else not divisible
Output number is divisible or not
Stop
Explanation:
Answer:
program arraysminfinder;
procedure minreplace();
var
no: array [1..10] of integer; (*no is an array of integers, 10 in all *)
a: integer= 0;
i: integer= 0;
c: integer= 0;
k: integer=0;
N: integer=0;
begin
(* We need to first initialize the array no with 0 values *)
for a := 1 to 10 do
no[a]:=0;
c:=no[1];
for a := 1 to 10 do
begin
if (no[i]<c) then
begin
c:=no[i];
k:=i;
end
else
begin
i:=i+1;
end
end;
writeln('Enter the new number:');
read(N);
no[k]:=N;
for a := 1 to 10 do
begin
writeln('The array elements are:',no[a]);
end;
end;
begin
end.
Explanation:
The program is as above. I have used a function, a for loop, an array of integers, and the if then else ladder for getting the desired output as mentioned in the program. If in case you want procedure for input and output, create a procedure like:
procedure replacenum():integer;
Begin
writeln("Enter the new number:" N);
no[k]:=N;
for a := 1 to 10 do
writeln("The array elements are:"no[a]);
end.
Similarly you can make a procedure for input.
Answer:
C++ Code:
void sort3(double &a, double &b, double &c)
{
if(a > b)
swapdoubles(a,b);
if (b > c)
swapdoubles(b,c);
if (a > b)
swapdoubles(a,b);
}
Explanation:
To change the values of a,b,c within the function, we pass the values by reference. Let us assume that number a = 3.14, b = 2.71, c = 3.04. Since a > b, values of a and b will be swapped.Now a = 2.71 and b = 3.14. Similariy, since b > c, they will be swapped. This way, we move the largest number to its correct position in the first two steps. If there are only three numbers, and the largest number is in its correct position, then for the two remaining numbers, we will only need atmost one swap to exchange their positions. hence, we perform a comparison of a > b once again to see if the b is smaller than a. if its not, then all a,b,c are in sorted order.
