Because of the reflection on the window or mirror.
Answer:
/*C++ program that prompts user to enter the name of input file(input.txt in this example) and print the sum of the values in the file to console. If file dosnot exist, then close the program */
//header files
#include <fstream>
#include<string>
#include <iostream>
#include <cstdlib> //needed for exit function
using namespace std;
//function prototype
int fileSum(string filename);
int main()
{
string filename;
cout << "Enter the name of the input file: ";
cin >> filename;
cout << "Sum: " << fileSum(filename) << endl;
system("pause");
return 0;
}
/*The function fileSum that takes the string filename and
count the sum of the values and returns the sum of the values*/
int fileSum(string filename)
{
//Create a ifstream object
ifstream fin;
//Open a file
fin.open(filename);
//Initialize sum to zero
int sum=0;
//Check if file exist
if(!fin)
{
cout<<"File does not exist ."<<endl;
system("pause");
exit(1);
}
else
{
int value;
//read file until end of file exist
while(fin>>value)
{
sum+=value;
}
}
return sum;
}//end of the fileSum
Explanation:
This is a C++ program that prompts user to enter the name of input file(input.txt in this example) and print the sum of the values in the file to console. If file dosnot exist, then close the program.
Check attachment for sample output screenshot.
It looks like you need to get both numbers from the input. Try doing something like this:
print(int(input()) + int(input()))
Answer:
The correct answer to the following question will be "Anonymous logon".
Explanation:
- Windows would never let anyone sign in interactively with an anonymous logon to the device, a person who has linked to the device without a login and password being given.
- So they won't have to verify to an account of the user just whether you are running any shares.r document, let everyone log into the machine collaboratively with such a logon.
Therefore, Anonymous logon is the right answer.