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Sergeeva-Olga [200]
3 years ago
6

Is 0.15 greater than 1.3

Mathematics
2 answers:
madam [21]3 years ago
8 0

Answer:

No.  1.3 is greater than 0.15.

Step-by-step explanation:

Rewrite 1.3 as 1.30.

This is more easily compared to 0.15, which also has 2 decimal places.

1.30 is greater than 0.15, and so 1.3 is certainly greater than 0.15 also.

Answer:  NO

eduard3 years ago
5 0

Answer:

No

Step-by-step explanation:

No because you have to look at the ones first

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Aint its good to have someone to love I swear its the best feeling of my life and shes freaky to i call her mamas and yes im bis
Mamont248 [21]

Answer:

yes

Step-by-step explanation:

why not purr bro I wish I had some one to love on

8 0
3 years ago
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Given the functions h(x) = 1/2x + 3 and j(x) = |x|, which value of x makes h(x) = j(x)?
Andrews [41]

Answer:

(1) or A or whatever lol

Step-by-step explanation:

basically just plug the number in, set them equal to each other, and see if the equation is true...

1/2(-2)+3=|-2|

-1+3=2

2=2

1/2(2)+3=|2|

1+3=2

4=2

1/2(3)+3=|3|

1.5+3=3

4.5=3

1/2(-6)+3=|-6|

-3+3=6

0=6

the only one that is a true statement is x=-2

8 0
3 years ago
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Ben and Tom each take their driving test. The probability that ben and tom will pass is 0.8 and 0.7, respectively. Work out the
Wittaler [7]

Answer:

Pr(only one of them will pass the driving test) = 0.38

Step-by-step explanation:

The probability that Ben will pass = 0.8

Let Pr = pribability

Pr(Ben pass) = 0.8

Pr(Ben fail) = 1 - Pr(Ben pass) = 1-0.8

Pr(Ben fail) = 0.2

The probability that Tom will pass = 0.7

Pr (Tom pass) = 0.7

Pr (Tom fail) = 1 - Pr (Tom pass) = 1-0.7

Pr (Tom fail) = 0.3

Pr(only one pass) = Pr(Ben pass and Tom fail) + Pr (Tom pass and Ben fail)

Pr(only one pass) = (0.8 × 0.3) + (0.7 × 0.2)

Pr(only one pass) = 0.24 + 0.14

Pr(only one pass) = 0.38

3 0
3 years ago
Can somebody help me? anybody know the answer
tigry1 [53]

Answer:

  25 = c

Step-by-step explanation:

You had a good start on filling in the values in the Pythagorean Theorem. The work needed to be finished.

  a^2 +b^2 = c^2\\\\20^2 +15^2=c^2\\\\400+225=c^2\\\\625=c^2\\\\\sqrt{625}=\sqrt{c^2}\\\\\boxed{25=c}

7 0
3 years ago
The graph of a proportional relationship passes through (12, 16)<br> and (1, y)<br> . Find y
k0ka [10]

Answer: The value of y is \frac{4}{3}.

Explanation:

It is given that the graph of a proportional relationship passes through (12, 16)

and (1, y).

The graph of a proportional relationship means the x and y coordinates are in a proportion k. The equation of the graph is in the form of y=kx. Where k is the proportion factor.

It is given that the graph passing through (12,16).

y=kx

16=k(12)

k=\frac{16}{12}

k =\frac{4}{3}

So the equation of the line is,

y=\frac{4}{3} x

put x=1.

y=\frac{4}{3} (1)

y=\frac{4}{3}

Therefore, the value of y is \frac{4}{3}.

8 0
4 years ago
Read 2 more answers
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