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Nesterboy [21]
2 years ago
14

Determine Upper P (Upper F or Upper G )using the general addition rule. Select the correct choice below and fill in any answer b

oxes within your choice. ​(Type the terms of your expression in the same order as they appear in the original expression. Round to three decimal places as​ needed.) A. Upper P (Upper F or Upper G )equals nothingplus nothingequals nothing B. Upper P (Upper F or Upper G )equals nothingplus nothingminus nothingequals nothing
Mathematics
1 answer:
Lilit [14]2 years ago
8 0

Answer:

S= {8 , 9 , 10 , 11 , 12 , 13 , 14 , 15 , 16 , 17 , 18 , 19 }

event F= {10 , 11 , 12 , 13 , 14}

event G= {14 , 15 , 16 , 17}

a) List of outcomes in F or G

answer;

(F or G) = { 10 , 11, 12 , 13 , 14 , 15 , 16 , 17}

b) P ( F or G) = by counting the number of outcomes in F or G  

Ans ( F or G) = No. of outcomes in ( F or G) / Total no. of outcomes

= 8/12 = 2/3

c) P ( F or G) using general addition rule

Ans P (F or G) = P(F) = P(G) - P( F and G)

      = 5/12 + 4/12 - 1/12

       = (5+4-1)/12 = 8/12 =2/3

Step-by-step explanation:

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Two expressions that equal 19
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<span>15+4=19</span>
5 0
3 years ago
1. Write the name of the properties:
faust18 [17]

Answer:

a) Commutative property of addition

b) Identity Property of Multiplication

c) Identity Property of Addition

d) Associative Property of Addition.

Step-by-step explanation:

6 0
1 year ago
49 is 200% of what number
finlep [7]
Idk howbto help u it could be 67 for all i know
4 0
3 years ago
An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up
Papessa [141]

Answer:

s(t)=-9.8t^2+49t+58.8

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form s(t)=-gt^2+v_0t+h_0, where

g = Force of gravity,

v_0 = Initial velocity,

h_0 = Initial height.

For our given scenario g=-9.8, v_0=49 and h_0=58.8. Upon substituting these values in object's height function, we will get:

s(t)=-9.8t^2+49t+58.8

Therefore, the function for the height of the arrow would be s(t)=-9.8t^2+49t+58.8.

6 0
3 years ago
(07.03)
Sloan [31]
The answer would be log base 2 of 6 over log base 2 of 3

8 0
3 years ago
Read 2 more answers
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