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4 years ago

Do the concepts of class limits, marks, cutpoints, and midpoints make sense for qualitative data? Explain your answer.

1 answer:

3 0

Class limits are the smallest and the largest data value that can go into a class.

Class marks are the midpoints of the classes. They are obtained by averaging the limits.

Cutpoints are specified values used to sort continuous variables into discrete categories.

Class Midpoint is the middle value of each data class.

For qualitative data, cutpoints and midpoints make sense, but class limits and marks do not, since qualitative data cannot be grouped using Limit grouping.

option D.

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If f(x) = 3x and g(x)= 1/x, what is the domain of (g*f) (f)?

lbvjy [14]

All real numbers or is it multiple choice

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3 years ago

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Two resistors, with resistances R1 and R2, are connected in series. R1 is normally distributed with mean 100 ohms and standard d

puteri [66]

Answer:

The probability that R2 is bigger than R1 is P=0.9633.

Step-by-step explanation:

We need to compute the probability that R2 is bigger than R1:

$P(R_2>R_1)$

To do this, we define a new variable Das the difference between the two resistances:

$D=R_2-R_1$

Then,

$P(R_2>R_1)=P(R_2-R_1>0)=P(D>0)$

As R1 and R2 are normal random variables, the properties of D are:

$\mu_D=\mu_{R2}-\mu_{R1}=120-100=20\\\\\sigma_D=\sqrt{\sigma_{R2}^2+\sigma_{R1}^2}=\sqrt{10^2+5^2}=\sqrt{100+25}=\sqrt{125}=11.18$

Then, we can calculate the z-value for D=0

$z=\frac{x-\mu}{\sigma} =\frac{0-20}{11.18}=\frac{-20}{11.18}= -1.79$

$P(D>0)=P(z>-1.79)=0.9633$

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3 years ago

In which of the scenarios below can you reverse the dependent and independent variables while keeping the interpretation of the

vichka [17]

Hey there,

Question : In which of the scenarios below can you reverse the dependent and independent variables while keeping the interpretation of the slope meaningful

Answer :I have come across this question before.. So I know the answer :D
As the time spent swimming increases, the number of calories burned in the body increases.

Hope this helps :))

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3 years ago

A road is inclined at an angle of 5°. After

Scorpion4ik [409]

Answer:

464 feet

Step-by-step explanation:

The Sine of the angle of inclination gives the increase in altitude.

This is because the Sine of an angle is equal to the Opposite side divided by the Hypotenuse side. i.e

Sin Ф = Opposite ÷ Hypotenuse

Sin 5° = O ÷ 5328

0·08716 = O ÷ 5328

Make O the subject and multiply every fraction by 5328

(0·08716/1 × 5328)= (O/5328 × 5328)

464·388 = O

∴ The increase in altitude is 464·388 feet

This is supposed to be to the nearest foot so we round off

464·388 becomes 464 feet

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3 years ago

Solve for p.

mrs_skeptik [129]

4(p+1.25)=725
divide by 4
p+1.25= 131.25
subtract 1.25 both sides
p = 130

hope it helps!!

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2 years ago

Read 2 more answers

Do the concepts of class​ limits, marks,​ cutpoints, and midpoints make sense for qualitative​ data? Explain your answer.

Do the concepts of class limits, marks, cutpoints, and midpoints make sense for qualitative data? Explain your answer.