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telo118 [61]
3 years ago
6

Kermit's favorite iced tea is made with 151515 tea bags in every 222 liters of water. Peggy made a 121212-liter batch of iced te

a with 909090 tea bags. What will Kermit think of Peggy's iced tea?
A. It is too strong.
B. It is too weak.
C. It is just right.
Mathematics
1 answer:
saw5 [17]3 years ago
3 0

Answer:

C. It is just right

Step-by-step explanation:

Kermit's Favorite iced tea:

Tea bags = 15

Water = 2 liters

Ratio of tea bags to water = 15 : 2

= 15/2

= 7.5

Peggy:

Tea bags = 90

Water = 12 liters

Ratio of tea bags to water = 90 : 12

= 90/12

= 7.5

C. It is just right

Kermit would think of Peggy's iced tea is just right

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kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

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\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

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