Given that the height of the disc is modeled by the function:
h=-16t^2+20t+6
a] The maximum height will be as follows:
At maximum height:
h'(t)=0
from h(t)
h'(t)=-32t+20=0
thus
t=20/32
t=5/8 sec
thus the maximum height will be:
h(5/8)=-16(5/8)^2+20(5/8)+6
=12.25 ft
b] <span>How long will it take the disc to reach the maximum height?
</span>time taken to reach maximum height will be:
from h(t)
h'(t)=-32t+20=0
thus
t=20/32
t=5/8 sec
thus time taken to reach maximum height is t=5/8 sec
c]<span>How long does it take for the disc to be caught 3 feet off the ground?
</span>h(t)=-16t^2+20t+6
but
h(t)=3
thus
3=-16t^2+20t+6
solving for t we get:
0=-16t^2+20t+3
factoring the above we get:
t=5/8-/+√37/8
t=-1.5256 or 2.776
since there is no negative time we pick t=2.776
Hence time taken for the disc to be caught 3 ft from the ground is 2.776 ft
Answer is D best luck bless you
10x-2y=10 We need to solve this equation for "y" to put it into slope intercept form:
10x-2y=10
-2y = -10x +10 Subtracted 10x from both sides
y = 5x - 5 Divided both sides by -2
y = 5x - 5 Is slope intercept form
Answer:
512
Step-by-step explanation:
You can figure this a couple of ways.
1) Figure the number of muffin boxes that goes into each dimension of the larger box:
(2 ft)/(3 in) = (24 in)/(3 in) = 8 . . . . muffin boxes in each direction.
Then the total number of muffin boxes that will fit in a larger box is ...
8×8×8 = 512
512 muffin boxes can fit into the larger box.
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2) The volume of a muffin box in cubic feet is ...
((3 in)/(12 in/ft))^3 = (1/4 ft)^3 = 1/64 ft^3
The volume of a larger box in cubic feet is ...
(2 ft)^3 = 8 ft^3
Then the number of smaller boxes that will fit in the larger box is ...
(8 ft^3)/(1/64 ft^3) = 8×64 = 512
512 muffin boxes can fit into the larger box.
The order does not matter. Algebraically we have y=12f(x3). Of our four transformations, (1) and (3) are in the x direction while (2) and (4) are in the y direction. The order matters whenever we combine a stretch and a translation in the same direction.