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mihalych1998 [28]
3 years ago
13

Please solve each equation & check your solution. Thank You!

Mathematics
1 answer:
Deffense [45]3 years ago
8 0

Answer:

G). 1.2x + 7.92 -3.3x = 41

-2.1x=33.08

x = 33.08/-2.1

x = - 15.752

H). 3x/2 + 9/5 = 12

Multiply through by 10

15x + 18 =120

15x =120-18

15x = 102

x =102/15

x=34/5

I). 5 = 9/4 - r/3

Multiply through by 12

60= 27 - 4r

60 - 27 = -4r

33 = - 4r

r = -33/4

J). 2(x - 2) = 12

2x - 4 = 12

2x = 16

x = 16/2

x = 8

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Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

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