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3 years ago

~HELP PLEASE~ What is the value of X?

Mathematics

2 answers:

Lyrx [107]3 years ago

7 0

The value of x is 75 I think

SashulF [63]3 years ago

3 0

I don’t know but your in higher math than me so can you help me on my questions please. Sorry I know that seems kinda selfish but I need help. I know how you feel. No one will help me.

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Solve for x.

AfilCa [17]

You need to put the numbers it give you, algo will am I supposed to solve that

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3 years ago

write the number 100 as a product of it's prime factor in the same way write the factors in order from smallest to largest

bearhunter [10]

Answer:

Thx for my points back

Step-by-step explanation:

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3 years ago

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Implicit diffrention problems I am really stuck on

AysviL [449]

Answer:

$\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}$

Step-by-step explanation:

solving for dy/dx

multiply the equation out to remove parentheses

$x^4 + x^3y = 5xy^2 -y^3$

now differentiating in terms of x ( $\frac{dy}{dx}$ )

$4x^3 +3x^2y + x^3(\frac{dy}{dx} ) = 5y^2 + 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )$

isolating dy/dx to one side

$4x^3 +3x^2y - 5y^2= 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )-x^3(\frac{dy}{dx} )$

$4x^3 +3x^2y - 5y^2= \frac{dy}{dx}(10xy-3y^2-x^3)$

$\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}$

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3 years ago

A cave explorer is at an elevation of negative 38 feet. The explorer starts moving at a rate of negative 12 feet per minute. Ide

Ksivusya [100]

Answer:

-38 - 12x < 200

Step-by-step explanation:

Given,

The original elevation = -38 feet,

Also, the explorer starts moving at a rate of negative 12 feet per minute.

So, the distance covered by explorer after x minutes = -12x feet,

Thus, the final elevation = original elevation + distance covered by explorer

= -38 - 12x

According to the question,

final elevation < -200 feet

⇒ -38 - 12x < 200

Which is the required inequality.

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