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Alex73 [517]
3 years ago
14

What is 48 months rounded to nearest hundredth ?

Mathematics
1 answer:
vladimir1956 [14]3 years ago
5 0
4.8 is the answer I’m pretty sure
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Points (-3,10) and (5,-2) are on a line. what is the slope of the line
lyudmila [28]
I believe it is-8,8 it’s been a while since I’ve done this so sorry if it is not correct
3 0
3 years ago
Write the equation of a circle with a center at (-2, 3) and a radius of 4.
Ivan

Answer:

The equation of a circle:

(x+2)^2+(y-3)^2 = 16

Step-by-step explanation:

The equation of a circle:

(x-h)^2+(y-k)^2 = r^2

(where the center is known as (h,k) and the radius, known as r).

-Since you already have the center and the radius, use them for the equation of a circle:

Center: (-2,3)

Radius: 4

(x+2)^2+(y-3)^2 = 4^2

After you have the equation of a circle, simplify the radius by the exponent 2 :

(x+2)^2+(y-3)^2 = 16

So, you have found the equation of a circle.

5 0
3 years ago
The Toy Company sells two types of kids' basketball hoops, Jordan size and Shaq size.
Hoochie [10]

Answer:

Maximum Profit = 13050

when

The Toy company sells Jordan Size hoops = 7

The Toy company sells Shaq Size hoops = 3

Step-by-step explanation:

Given - The Toy Company sells two types of kids' basketball hoops, Jordan size and Shaq size.  A neighborhood needs no more than 10 Jordan sizes and Shaq sizes all together. The  Company requires the neighborhood to order at least 2 Jordan sizes and at least 3  Shaq sizes. The Toy Company makes a profit of $1,350 on the Jordan size and $1,200  on the Shaq size.

To find - What is the maximum profit they can make given the constraints  above?

Proof -

Let us assume that,

The Toy company sells Jordan Size hoops = x

The Toy company sells Shaq Size hoops = y

Now,

Given that,  A neighborhood needs no more than 10 Jordan sizes and Shaq sizes all together.

⇒x + y ≤ 10

Now,

Given that,  The  Company requires the neighborhood to order at least 2 Jordan sizes and at least 3  Shaq sizes.

⇒ x ≥ 2

   y ≥ 3

Now,

Given that,

The Toy Company makes a profit of $1,350 on the Jordan size and $1,200  on the Shaq size.

So,

The objective function becomes

Z = 1350x + 1200 y

So,

The Linear Programming Problem (LPP) becomes

Maximize Z = 1350x + 1200 y

Subject to

x + y ≤ 10

x ≥ 2

y ≥ 3

x, y ≥ 0

We will Solve the LPP by Graphical method.

The graph is as follows :

The points on the Boundary are -

A(2, 8)

B(2, 3)

C(7, 3)

So,

Points (x,y) Objective function value  ( Z = 1350x + 1200y)

B(2,3)            1350(2) + 1200(3) = 6300

C(7,3)           1350(7) + 1200(3) = 13050

A(2,8)                 1350(2) + 1200(8) = 12300

So,

Maximum value = 13050 at point C(7,3)

∴ we get

Maximum Profit = 13050

when

The Toy company sells Jordan Size hoops = x = 7

The Toy company sells Shaq Size hoops = y = 3

6 0
3 years ago
. The Bakers Dozen bakery sells apple, cherry, and pumpkin pies.Yesterday, the bakery sold 14 more apple pies than cherry pies a
Dominik [7]

Answer:

They sold 40 pies in total. Hope this helped =)

3 0
3 years ago
Read 2 more answers
PLEASE HELP! Will give brainliest! A bag contains 5 pink marbles and 6 green marbles. Two marbles will be selected one at a time
Karolina [17]

Answer:

The selection of the two marbles are <u>dependent</u> because the selection of the pink marble <u>changes</u> the probability that a green marble is drawn next.

If the pink marble had been put back into the bag, the selection of the two marbles would have been <u>independent</u>

======================================================

Explanation:

The key phrase to focus on here is "This marble is placed on a table". It implies that we do not put it back into the bag, and also implies we don't put in a replacement either. Hence we consider this scenario as "no replacement".

In no replacement situations, we always have dependent events. The second selection depends on the first one.

The probability of picking green is 6/11 because there are 6 green out of 5+6 = 11 total. But if we picked a pink one first and didn't put it back, then the 11 drops to 10 and we get 6/10 = 3/5 as the new probability.

In other words,

  • before the pink marble is selected, the chances of green are 6/11
  • after the pink marble is selected, and not put back, the chances of green are now 6/10 = 3/5

Because this probability changes, it's sufficient evidence to say the event of picking green on the second selection is dependent on the first selection of selecting pink.

If the marble had been put back, then we'd revert back to the original state of the bag. That would mean the chances of green would stay at 6/11. Therefore, situations with replacement lead to independent events.

5 0
2 years ago
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