Answer:
45.05 seconds
Step-by-step explanation:
Use the formula: d = v t +
 t +  a
 a
d = distance      v = initial velocity (m/s)
 = initial velocity (m/s)    
t = time (s)     a = acceleration (m/ )
)
m is meters and s is seconds. They are units of measurement so leave them be. 
Assuming the object is simply dropped, the initial velocity is 0 since the object was not moving before it was dropped. 
The distance is 725 feet, which is 220.98 meters. 
The acceleration is 9.81m/ since that is the acceleration of Earth's gravity, aka free fall.
 since that is the acceleration of Earth's gravity, aka free fall. 
Time is what we are trying to find so just leave it as the variable t.
So plug the values into the equation:
220.98m = (0)(t) +  (9.81m/
 (9.81m/ )(t)
)(t)
220.98m = (4.905m/ )(t)
)(t)
45.0519877676s = t
t = 45.05s
Remember to pay attention to units because your answer will be wrong otherwise
 
        
             
        
        
        
Answer: Y=-1 
Explanation: 2y-3=y-4 (add three on both sides) 
 2y=y-1 (subtract y on both sides)
 y=-1
        
             
        
        
        
Answer:
C
Step-by-step explanation:
Using Pythagoras' identity to determine if the triangle is right
The square of the longest side should equal the sum of the squares on the other 2 sides, that is
QS² = RS² + QR² = 8² + 5² = 64 + 25 = 89 ( take the square root of both sides )
QS = 
Δ QRS is not right as QS would have to be 
 
        
                    
             
        
        
        
Dilation refers to a non rigid motion where a figure is transform and its image has the same form but a different size measure.
Dilation is define by the rule (x,y)-- (kx, ky) where k represents the scale factor.
On this exercise is given that a triangle with vertices (-2,1), (8,4), and (3,0) was dilated by a scale factor of four, and it is asked to find the vertices of the image of the triangle after the dilation occurred.
Pre-image                       Image
(-2,1)  --   (-2*4,1*4)   --   (-8,4)
(8,4)   --    (8*4,4*4)   --    (32,16)
(3,0)   --    (3*4,0*4)   --    (12,0)
The coordinates representing the vertices of the triangle's image are (-8,4), (32,16), and (12,0); meaning that the ordered pair which is not a coordinate for a point in the triangle's image is (2,1).