the answer would be 
because you would need to find the LCD, which in this case would be 56 and you solve from there.
Answer:
Do you want to be extremely boring?
Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?
is a valid solution.
Want something more fun? Why not a parabola? 
.
At this point you have three parameters to play with, and from the fact that 
we can already fix one of them, in particular 
. At this point I would recommend picking an easy value for one of the two, let's say 
(or even 
, it will just flip everything upside down) and find out b accordingly:
Our function becomes
Notice that it works even by switching sign in the first two terms: 
Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: 
Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need 
, and at that point the first condition is guaranteed; using the second to find k we get 
Or how about a sine wave that oscillates around 2? with a similar reasoning you get
Sky is the limit.
<span>1.Take the principle square root of a negative number.
2 Write a complex number in standard form.
3.Add and subtract complex numbers.
4.Multiply complex numbers.
5. Divide complex numbers.</span>
Answer: y = 2x - 2
Explanation: The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
y = mx + b
Subtract 2x from both sides of the equation.
-y = 2 - 2x
Multiply each term in -y = 2 - 2x by -1
(-y) . -1 = 2 . -1 + (-2x) . -1
Multiply (-y) . -1
Multiply -1 by -1
Multiply y by 1
y = 2 . -1 + (-2x) . -1
Simplify each term
Multiply 2 by -1
y = -2 + (-2x) . -1
Multiply -1 by -2
y = -2 + 2x
Reorder -2 and 2x
y = 2x - 2
80-6×8= answer decrease is reduced..... does this help
