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Delicious77 [7]
3 years ago
14

What is 3a-2b if a=-1 and b=-2

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0
3(-1) - 2(-2)

-3 + 4 = 1

your answer is 1

remember, two negatives become one postive
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After going trick-or-treating, Cheyan is trying to
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Answer:

16

Step-by-step explanation:

All you have to do is add 14+34 which is 48. Since you know that she averaged 3 pieces of candy you have to divide 48 and 3 which is 16

3 0
3 years ago
Read 2 more answers
Part A: Solve –vp + 30 < 45 for p. Show your work.
Butoxors [25]
Part A: subtract 30 from both sides to get -vp<45. Then divide both sides by -v and flip the signs to get p>45/-v

Part B: subtract 3w from both sides to get -6r=30. Then divide -6 by both sides to get 3w/-6-5=r
8 0
3 years ago
Please answer this question for me. dont scam i have an exam tomorrow
Vanyuwa [196]

Answer:

(C) α + β + γ

Step-by-step explanation:

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6 0
3 years ago
There were 42 students who took a test in mathematics.there were 36 students who passed test 1, and there were 38 who passed tes
Keith_Richards [23]
We are giiven with two realms:  36 students who passed test 1 and <span>38 who passed test 2 in which 42 students overall took the test. to determine U' or those who didn't pass either of the tests, then we use the formula:  
A or B = (A+B)-AandB
A/B = (36+38)-AandB= 74-AandB
42 = A+ B - AandB + U'; 42 = 74-  AandB+ U'

where U' is the number who did not pass

U'= -32 + AandB
U' cannot be negative but can be zero,
AandB = 32 @ minimum number of those who fail.
AandB cannot be greater than 38 but can be greater than 36, hence
U' = -32 + 38 @ maximum number of those who fail.

Answer then is 6. 


</span>
7 0
3 years ago
False. consider u1 = (0, 0, 0), u2 = (1, 0, 0), u3 = (0, 1, 0), and u4 = (0, 0, 1).
Vaselesa [24]
You give us the answer right now. It's the answer to : 

<span>If {u1, u2, u3} does not span R3, then neither does {u1, u2, u3, u4}.
</span>
Hope this helps !

Photon
8 0
4 years ago
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