Answer:
x = -44/13
y = -65/13
Step-by-step explanation:
Using matrix form means using the crammers rule
The matrix form of the expression is written as;
![\left[\begin{array}{ccc}8&5\\-1&1\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}9\\7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%265%5C%5C-1%261%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%5C%5C7%5C%5C%5Cend%7Barray%7D%5Cright%5D)
AX = B
taking the determinant of A;
|A| = 8(1) - 5(-1)
|A| = 8 + 5
|A| = 13
After replacing the first row with the column matrix;
![A_x =\left[\begin{array}{ccc}9&5\\7&-1\\\end{array}\right]](https://tex.z-dn.net/?f=A_x%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%265%5C%5C7%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
|Ax| = 9(-1)-5(7)
||Ax| = -9 - 35
|Ax| = -44
x = |Ax|/|A|
x = -44/13
similarly for y
![A_x =\left[\begin{array}{ccc}8&9\\-1&7\\\end{array}\right]](https://tex.z-dn.net/?f=A_x%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%269%5C%5C-1%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
|Ay| = 8(7)+9
|Ay| = 56+9
|Ay| = 65
y = |Ay|/|A|
y = -65/13
Answer:
sq root of 64 = 8, sq root of 81 = 9, 8 and 9
Step-by-step explanation:
Since Sq root of 64 = 8 and Sq root of 81 = 9 it is known that sq root of 66 is between 8 and 9
Answer:
Step-by-step explanation:
We have the different denominators.
The common denominator is 10.
We can subtract these fractions now.
Answer:
hon you never asked a question or added an image. id be happy to try and help if you do!
Y-8=-1/2x + (-2)
+8 +8
y=-1/2x +6
I just used a 2 step equation for it. I first used Distributive Property. Then Subtracted 8 from each side
