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DaniilM [7]
3 years ago
7

What’s 6 times -1 times 2

Mathematics
1 answer:
ki77a [65]3 years ago
5 0
6 times -1 times 2 it equals -12
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80 - [50 - {20 ÷ 2 – (16 - 2÷ 2) ÷ 3}]
trapecia [35]

Answer:

35

Step-by-step explanation:

We have to solve the problems in the parenthesis first.

(16-2÷2)= (16-1)=(15)

20÷2-15÷3

(20÷2)-(15÷3)

10-5=5

50-5= 45

80-45= 35

Hope this helps!

6 0
3 years ago
HELPPPP what do I do exactly ?
MAXImum [283]

Answer:


Step-by-step explanation:

Note that the squaring function and the square root function are inverses of one another.  If we make a list of perfect squares, we get {1, 4, 9, 16, 25, ...}.  Then the square roots of these numbers are {1, 2, 3, 4, 5, ... }.

Continue making a table of values to plot.  The first row has x=0, y=0; this reflects that the sqrt of 0 is 0.

Fill the first (x-) column with perfect squares and the second (y-) column with the square roots of these perfect squares:

x   y

0   0

1    1

4    2

9    3

and so on.

Now plot the following on the graph:  (1,1), (4,2), (9,3), ....  

Starting at (0,0) and moving to the right (indicating increases in x), plot these  points.  (You'll soon run out of room.)  Draw a smooth curve from (0,0) to connect these points.  The result is a graph of the square root function.

The domain of this function is "the set of all real numbers ≥0" and the range is the same:  "the set of all real numbers ≥0"

4 0
3 years ago
Read 2 more answers
PLSS HELP IF YOU TURLY KNOW THISS
coldgirl [10]

Answer:

x = 7

Step-by-step explanation:

7x = 49

7x \div 7 = 49 \div 7

x = 49 \div 7 = 7

\boxed{\green{x = 7}}

3 0
2 years ago
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Which of the following are valid names for the given triangle? Check all that apply.
vfiekz [6]
When naming triangles we name them by the letters on each corner so only answers with T, A, and X in them are correct, so TAX, XTA, and AXT
6 0
3 years ago
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Please help me with problem 2 of a math problem
nikklg [1K]

Answer:

C, 7 1/2

Step-by-step explanation:

You add all of the fractions together.

7 0
3 years ago
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