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Alla [95]
3 years ago
7

If f(x) = -x + 5 and g(x) = x^2, what is (g*f)(-1)

Mathematics
2 answers:
Rama09 [41]3 years ago
5 0

Answer:

9

Step-by-step explanation:

leonid [27]3 years ago
5 0

The answer to your question is 9

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Ill give you brainliest if you answer this question!​
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3 years ago
Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving
harina [27]

Answer:

The volume of the solid is 714.887 units³

Step-by-step explanation:

* Lets talk about the shell method

- The shell method is to finding the volume by decomposing

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- Consider a region in the plane that is divided into thin vertical

 rectangle

- If each vertical rectangle is revolved about the y-axis, we

 obtain a cylindrical shell, with the top and bottom removed.

- The resulting volume of the cylindrical shell is the surface area

  of the cylinder times the thickness of the cylinder

- The formula for the volume will be:  V = \int\limits^a_b {2\pi xf(x)} \, dx,

  where 2πx · f(x) is the surface area of the cylinder shell and

  dx is its thickness

* Lets solve the problem

∵ y = x^{\frac{5}{2}}

∵ The plane region is revolving about the y-axis

∵ y = 32 and x = 0

- Lets find the volume by the shell method

- The definite integral are x = 0 and the value of x when y = 32

- Lets find the value of x when y = 0

∵ y = x^{\frac{5}{2}}

∵ y = 32

∴ 32=x^{\frac{5}{2}}

- We will use this rule to find x, if x^{\frac{a}{b}}=c, then=== x=c^{\frac{b}{a}} , where c

 is a constant

∴ x=(32)^{\frac{2}{5}}=4

∴ The definite integral are x = 0 , x = 4

- Now we will use the rule

∵ V = \int\limits^a_b {2\pi}xf(x) \, dx

∵ y = f(x) = x^(5/2) , a = 4 , b = 0

∴ V=2\pi \int\limits^4_0 {x}.x^{\frac{5}{2}}\, dx

- simplify x(x^5/2) by adding their power

∴ V = 2\pi \int\limits^4_0 {x^{\frac{7}{2}}} \, dx

- The rule of integration of x^{n} is ==== \frac{x^{n+1}}{(n+1)}

∴ V = 2\pi \int\limits^4_0 {x^{\frac{9}{2}}} \, dx=2\pi[\frac{x^{\frac{9}{2}}}{\frac{9}{2}}] from x = 0 to x = 4

∴ V=2\pi[\frac{2}{9}x^{\frac{9}{2}}] from x = 0 to x = 4

- Substitute x = 4 and x = 0

∴ V=2\pi[\frac{2}{9}(4)^{\frac{9}{2}}-\frac{2}{9}(0)^{\frac{9}{2}}}]=2\pi[\frac{1024}{9}-0]

∴ V=\frac{2048}{9}\pi=714.887

* The volume of the solid is 714.887 units³

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3 years ago
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