Question

I have no clue what the answer is.

Answer 1

Area of the word ME = 20 square units

Solution:

Picks' Theorem:

$Area=I+\frac{B}{2}-1$

where I is the interior points and B is the points on the boundary.

Let us first find the area of the letter M:

Number of interior points in M = 0

Number of points in the boundary = 22

Using pick's theorem,

Area of M = $0+\frac{22}{2}-1$

Area of M = 10 square units

Now, find the area of the letter E:

Number of interior points in E = 0

Number of points in the boundary = 22

Using pick's theorem,

Area of E = $0+\frac{22}{2}-1$

Area of E = 10 square units

Area of the word ME = Area of M + Area of E

                                   = 10 square units + 10 square units

Area of the word ME = 20 square units