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svlad2 [7]
2 years ago
11

Suppose you know that the distribution of sample proportions of fifth grade students in a large school district who read below g

rade level in samples of 100 students is normal with a mean of 0.30 and a standard deviation of 0.12. You select a sample of 100 fifth grade students from this district and find that the proportion who read below grade level in the sample is 0.54. This sample proportion lies 2.0 standard deviations above the mean of the sampling distribution. What is the probability that a second sample would be selected with a proportion greater than 0.54 ?
Mathematics
1 answer:
Brut [27]2 years ago
6 0

Based on the mean of the sample and the proportion who read below grade level, the probability that a second sample would have a proportion greater than 0.54 is 0.9772.

<h3>What is the probability of the second sample being greater than 0.54?</h3>

The probability that the second sample would be selected with a proportion greater than 0.54 can be found as:

P (x > 0.54) = P ( z > (0.54 - 0.30) / 0.12))

Solving gives:

P (x > 0.54) = P (z > 2)

P (x > 0.54) = 0.9772

In conclusion, the probability that the second sample would be selected with a proportion greater than 0.54 is 0.9772.

Find out more on probability at brainly.com/question/25638875

#SPJ1

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Answer:  (D) <em>bottom right graph</em>

<u>Step-by-step explanation:</u>

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Given g(x) = (x - 3)² - 5

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3 years ago
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Step-by-step explanation:

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3 years ago
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The Brady family received 1 letter on July 28.

Step-by-step explanation:

Step 1:

Assume a = the number of letters, b = the number of bills, c = the number of ads, and d = the number of magazines.

From the question, they got 15 pieces of mail that day so a+b+c+d=15.

They got 5 more magazines than bills so d = b + 5.

The got the same number of letters as ads so a=c.

They got 3 more bills than ads so b= c + 3.

Step 2:

As we have only one equation to solve the values, we need to make every term in terms of a single term.

We make everything in terms of c.

So a=c, b = c+3, c=c, d = b+5 = (c+3)+5=c+8.

Substituting all this in the equation, we get

a + b+c+d =(c)+(c+3)+(c)+(c+8) = 15, 4c+11=15.

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Step 3:

Substituting c = 1 in other terms, we get

a=c=1,

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The question provides one endpoint and then the midpoint. The midpoint on the coordinate grid is (0, -7) and one endpoint is (-2,-6).

The formula for calculting the midpoint is given as follows;

\begin{gathered} M=\frac{x1+x2}{2},\frac{y1+y2}{2} \\ Take\text{ the x coordinates and y coordinates one after the other,} \\ 0,7=\frac{-2+x2}{2},\frac{-6+y2}{2} \\ \text{The x coordinates and the midpoint coordinate are} \\ 0=\frac{-2+x2}{2} \\ \text{Cross multiply and you have;} \\ 0=-2+x2 \\ 2=x2 \\ \text{The y coordinates and the midpoint coordinates are;} \\ 7=\frac{-6+y2}{2} \\ \text{Cross multiply and you have;} \\ 14=-6+y2 \\ 14+6=y2 \\ 20=y2 \\ \text{Therefore, the coordinates for the other midpoint is derived as;} \\ (2,20) \end{gathered}

Therefore, the coordinates of B is calculated as (2, 20)

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