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Inessa [10]
3 years ago
5

Choose the correct simplification of the expression (2x2y6z5)(5x4y5z3).

Mathematics
1 answer:
erastovalidia [21]3 years ago
8 0

Answer:

The correct option is 4.

Step-by-step explanation:

The given expression is

(2x^2y^6z^5)(5x^4y^5z^3)

Simplify the given expression.

(2x^2y^6z^5)\times (5x^4y^5z^3)

(2\times 5)(x^2x^4)(y^6y^5)(z^5z^3)

10x^{2+4}y^{6+5}z^{5+3}                  [\because x^mx^n=x^{m+n}]

10x^6y^{11}z^8

Therefore correct option is 4.

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Which point on the axis satisfies the inequality y<x​
Vika [28.1K]

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every point where x is greater than y or  y-x<0

namely, every point below the straight line y=x that cuts the cartesian plane in two

Step-by-step explanation:

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3 years ago
Which graph shows the equation y = x - 2?
kondaur [170]

Answer:

Choice A

Step-by-step explanation:

6 0
3 years ago
The area of Mark's laptop computer
navik [9.2K]

Answer:

4x+1

Step-by-step explanation:

The area is 12x2 + 3x in

The length is 3x

Formula is A=L*B

12x2 + 3x=3x*B

Divide both side by 3x

12x2+3x divide by 3x=B

4x+1=B

The express for the width is 4x+1

Please mark as brainliest

7 0
3 years ago
3. Tom, Sam and Matt are counting drum beats.
just olya [345]

Answer:

<em>When 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.</em>

Step-by-step explanation:

The Least Common Multiple ( LCM )

The LCM of two integers a,b is the smallest positive integer that is evenly divisible by both a and b.

For example:

LCM(20,8)=40

LCM(35,18)=630

Since Tom, Sam, and Matt are counting drum beats at their own frequency, we must find the least common multiple of all their beats frequency.

Find the LCM of 4,10,12. Follow this procedure:

List prime factorization of all the numbers:

4 = 2*2

10 = 2*5

12 = 2*2*3

Multiply all the factors the greatest times they occur:

LCM=2*2*3*5=60

Thus, when 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.

6 0
3 years ago
An unfair coin with​ Pr[H] = 0.2 is flipped. If the flip results in a​ head, a marble is selected at random from a urn containin
satela [25.4K]
Normally when dealing with coins the probability of getting heads or tails is 0.5 each. However in this case since its an unfair coin, the probability of getting heads is 0.2. 
H - head 
T - tails
R - red marble
pr (H) = 0.2
urn
6 red and 4 blue
pr (T)   = 0.8
urn
3 red and 5 blue

when heads is obtained 
red - 6/10 -0.6
blue - 4/10 - 0.4
therefore when multiplying with 0.2 probability of getting heads
pr (R ∩ H) red - 0.6*0.2 = 0.12

when tails is obtained 
red - 3/8 - 0.375
blue - 5/8 - 0.625
when multiplying with 0.8 probability of getting tails
pr (R ∩ T) red - 0.375 * 0.8 = 0.3

using bayes rule the answer can be found out, 
the following equation is used;
pr (H | R) = pr (R ∩ H) / {pr (R ∩ H) + pr (R ∩ T)}
               = 0.12 / (0.12 + 0.3)
               = 0.12 / 0.42
               = 0.286
the final answer is 0.286
6 0
3 years ago
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