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kicyunya [14]
3 years ago
13

A 20 ft ladder leans against a wall. The base of the ladder is 5 ft from wall. How high up the wall does the top of the ladder r

each? a)19.4
b)20.6
c)375
d)15 ft​
Mathematics
1 answer:
Archy [21]3 years ago
7 0
Let h = height
h square = 20 square + 5 square
h square = 400+ 25
So you square root both sides
h = root 425
h = 20.6155281

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Middletown sponsors a two day conference for selected middle school students to study government. Suppose 20 student delegates w
grandymaker [24]

Answer:

  • North Middle School = 10 students
  • Central Middle School = 6 students
  • South Middle School = 4 students

Step-by-step explanation:

First calculate the total number of students in all the schools:

= 618 + 378 + 204  

= 1,200 students

Use this number to calculate the proportion of the total population that a school so that this can then be used to determine the proportion of the 20 delegates they should sent.

North Middle school:  

= 618/1,200 * 20  

= 10 students

 

Central Middle School:  

= 378 / 1,200 * 20  

= 6 students

 

South Middle School:  

= 204/1,200 * 20  

= 4 students  

5 0
2 years ago
If 1/a + 1/b =1/c and ab=c,what is the average of a and b?
goblinko [34]
If we solve the left side of the given equation,
                                  1/a + 1/b = 1/c
 we get an answer of,
                                    b+a / ab = 1/c
Since ab = c, we can conclude that b + a is 1. The average of these two numbers is equal to there sum divided by 2. The answer is therefore equal to 0.5. 
4 0
3 years ago
Lim x-&gt;-5(((1)/(5)+(1)/(x))/(10+2x))=<br><br>correct answer 1/10x = -1/50<br><br>explain:
slava [35]

Given:

The limit problem is:

lim_{x\to -5}\dfrac{\dfrac{1}{5}+\dfrac{1}{x}}{10+2x}

To find:

The value of the given limit problem.

Solution:

We have,

lim_{x\to -5}\dfrac{\dfrac{1}{5}+\dfrac{1}{x}}{10+2x}

It can be written as:

=lim_{x\to -5}\dfrac{\dfrac{x+5}{5x}}{2(5+x)}

=lim_{x\to -5}\dfrac{x+5}{5x}\times \dfrac{1}{2(5+x)}

=lim_{x\to -5}\dfrac{1}{5x\times 2}

=lim_{x\to -5}\dfrac{1}{10x}

Applying limit, we get

lim_{x\to -5}\dfrac{1}{10x}=\dfrac{1}{10(-5)}

lim_{x\to -5}\dfrac{1}{10x}=\dfrac{1}{-50}

Therefore, the value of given limit problem is -\dfrac{1}{50}.

6 0
2 years ago
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