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AURORKA [14]
4 years ago
8

What is 9.01x10^3 in scientific notation

Mathematics
1 answer:
Alchen [17]4 years ago
7 0
9.01 * 10^3 in scientific notation is 9.01 * 10^3.

I got this answer by moving the decimal so there is a non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent of the 10. If the decimal is binge move to the right, the exponent will be negative, but if the decimal is being moved to the left the exponent will be positive.

I hope this helps! :>
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Two angles of a triangle are 47 and 32 degrees. Select all angles that could represent exterior angles of a triangle.
notsponge [240]

Answer:

133, 79, 148 are ALL possible, so select 133 and 79

Step-by-step explanation:

Subtract 47 and 32 from 180 to find the third angle of the triangle (it is 101).

Then do 180-101 = 79

180-32=148

180-47=133

That tells you the exterior angle of each. Only two possible choices on your list.

3 0
2 years ago
In order to make the expression below equivalent to ğ x + 6, which additional operation should be included in the
kakasveta [241]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
I have a rectangle that is 2 1/2 feet long and 1 1/3 feet wide. What is the area of the rectangle? Please show work
bezimeni [28]
I cant really attach a picture but this is the answer so you turn 2 1/2 into a improper fraction which is 5/2. then you multiply 11/3*5/2. And that equals 55/6. and then turn it into a whole number and it equals 9.16..
5 0
3 years ago
The height of a tree is 8 metres, correct to the nearest metre.
finlep [7]
B or D i calculated the answer and it was between B and D
8 0
3 years ago
Suppose that, in addition to edge capacities, a flow network has vertex capacities. That is each vertex has a limit l./ on how m
storchak [24]

Answer:

See explanation and answer below.

Step-by-step explanation:

The tranformation

For this case we need to construct G' dividing making a division for each vertex v of G into 3 edges that on this case are v_1, v_2 and l(v).

We assume that the edges from the begin are the incoming edges of v_1 and all the outgoing edges from v are outgoing edges from v_2

We need to construct G' = (V', E') with capacity function a' and we need to satisfy the follwoing:

For every v \in V we create 2 vertices v_1, v_2 \in V'

Now we can add a new edge asscoiated to v_1, v_2 \in E' with the condition a' (v_1,v_2) = l(v)

Now for each edges (u,v)\in E we can create the following edge ( u_r, v_1) \in E' and the capacity is given by: a' (u_r, v_1) = a (u,v)

And for this case we can see this:

|V'| = 2|V|, |E'|= |E| +|V|

Now we assume that x is the flow who belongs to G respect vertex capabilities. We can create a flow function x' who belongs to G' with the following steps:

For every edge (u,v) \in G we can assume that x' (u_r ,v_1) = x(u,v)

Then for each vertex u \in V -t and we can define x\(u_1,u_r) = \sum_{v \in V} x(u,v) and x' (t_1,t_2) = \sum_{v \in V} x(v,t)

And after see that the capacity constraint on this case would be satisfied since for every edge in G' on the form (u_r, u_1) we have a corresponding edge in G because:

u \in V -(s,t) we have that:

x' (u_1, u_r) = \sum_{v \in V} x(u,v) \leq l(u) = a' (u_1, u_r)

x' (t_1,t_2) = \sum_{v \in V} x(v,t) \leq (t) = a' (t_1,t_2)

And with this we have the maximization problem solved.  

We assume that we have K vertices using the max scale algorithm.

6 0
3 years ago
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