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givi [52]
3 years ago
5

Farmer Smith enclosed his rectangular pasture with fence that cost him $1.50 per linear meter. If his pasture is twice as long a

s it is wide with a total area of 180,000 square meters, then what was the cost, in dollars, of the fence?
Mathematics
1 answer:
maria [59]3 years ago
6 0

Answer:

$2,700

Step-by-step explanation:

Let the width of the pasture be x, this means that the length of the pasture will be 2x

The area of a rectangle is L * B

Hence,

x * 2x = 18,000

2x^2 = 180,000

x^2 = 90000

x = 300 meters

This means the length is 600 metres

Now, to get the length of the fence, we need to know the actual perimeter which is 2(L + B)

= 2 ( 300 + 600)

2 * 900 = 1,800 metres

The cost is thus 1,800 * $1.50 = $2,700

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Step-by-step explanation:

Considering 'y' be the number

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solving

\begin{bmatrix}y=2x+3\\ y=2x+1\end{bmatrix}

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\begin{bmatrix}2x+1=2x+3\end{bmatrix}

\mathrm{Refine\:}2x+1=2x+3

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\mathrm{No\:Solution}

Therefore, there is NO solution.

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