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givi [52]
3 years ago
5

Farmer Smith enclosed his rectangular pasture with fence that cost him $1.50 per linear meter. If his pasture is twice as long a

s it is wide with a total area of 180,000 square meters, then what was the cost, in dollars, of the fence?
Mathematics
1 answer:
maria [59]3 years ago
6 0

Answer:

$2,700

Step-by-step explanation:

Let the width of the pasture be x, this means that the length of the pasture will be 2x

The area of a rectangle is L * B

Hence,

x * 2x = 18,000

2x^2 = 180,000

x^2 = 90000

x = 300 meters

This means the length is 600 metres

Now, to get the length of the fence, we need to know the actual perimeter which is 2(L + B)

= 2 ( 300 + 600)

2 * 900 = 1,800 metres

The cost is thus 1,800 * $1.50 = $2,700

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Answer:

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2 years ago
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Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

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\frac{15*85*15}{100*100*100} = \frac{19,125}{1,000,000} = \frac{1.9125}{100}

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