Answer: The distance of Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?
It is 1/4.
Step-by-step explanation:
We know that the intensity of electromagnetic waves decreases with the radius squared, this means that we can write a simple relation as:
Intensity(r) = A/r^2
Observer A measures 16 the intensity of observer B.
if Ia is the intensity that observer A measures and Ib is the intensity that observer B measures, we have that:
Ia = 16Ib
A/(ra)^2 = 16*A/(rb)^2
1/(ra)^2 = 16/(rb)^2
rb^2 = 16*ra^2
and we know that 16 = 4*4 = 4^2
rb^2 = (4*ra)^2
then rb = 4*ra
this means that the distance between observer B and the antenna is equal to 4 times the distance between observer A and the antenna.
The fraction is ra = rb/4
The distance of
Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?
It is 1/4.
Answer:
and 
Step-by-step explanation:
Let
x -----> the altitude of a commercial aircraft
we know that
The expression " A minimum altitude of 29,000 feet" is equal to
All real numbers greater than or equal to 29,000 ft
The expression " A maximum altitude of 41,000 feet" is equal to
All real numbers less than or equal to 41,000 ft
therefore
The compound inequality is equal to
and
All real numbers greater than or equal to 29,000 ft and less than or equal to 41,000 ft
The solution is the interval ------> [29,000,41,000]
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The answer to the missing side length would be .75
