Question

(Giving 100 pts, help fast!!!) Four congruent square pieces with lengths of sides of 6 cm were cut out of corners of a square piece of cardboard. Then this piece of cardboard was folded into an open-top box. Find the original dimensions of the piece of cardboard if the volume of the resulting box is 486 cm3.

Answer 1

Answer:

21x21 cm

Step-by-step explanation:

Volume =whl

Given: V=486, and h=6, and w=l

So we can it into this equation: 486=6(l^2)

to solve we isolate the variable by dividing each side by factors that don't contain the variable.

which therefore l = 9

Then we add 6(height) +9(l)+6(width)

6+9+6=21 therefore the sides of cardboard are 21 cm × 21 cm

Answer 2

Answer:

21cm^2

Step-by-step explanation:

V=B*h

B=(x-12)^2

h=6

(x-12)^2*6=486

Solve using quadratic equation and you get 21 and 3.

3 doesn't work so it is 21