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egoroff_w [7]
3 years ago
12

Express x in term of y:x/7+2y=6​

Mathematics
1 answer:
lions [1.4K]3 years ago
8 0

Answer:

You have to multiply the denorminator to both sides in order to make x the subject :

\frac{x}{7 + 2y}  = 6

x = 6(7 + 2y)

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Which graph correctly matches the equation y = 2-x?
nalin [4]

Answer:  The answer is attached in the figure.


Step-by-step explanation:  Given are four different graphs and we are to check which one matches with the equation y = 2 - x.

We have the following points on this equation.

(0,2), (1,1), (2,0), etc.

When we try to match these points with the given graphs, the we see that these points does not match with the first, third and fourth graph. The only graph containing these points is second one.

Thus, the second option is correct. Also see the attached figure for the location of the three mentioned points.


4 0
2 years ago
Read 2 more answers
An orange has about 1/4 cup of juice. How many oranges are needed to make 2 1/2 cups of juice?
Vesna [10]

Answer:

10 oranges

Step-by-step explanation:

4 oranges are needed to make one cup. 2 cups is 8 oranges and 1/2 cup is 2 oranges

8 0
2 years ago
Graph the solution set of this inequality 3x-2y <_ 12
nadezda [96]

The graph of the solution set for the inequality can be seen below.

<h3>How to graph the solution set?</h3>

Here we have the inequality:

3x - 2y < -12

If we isolate y, we get:

3x + 12 < 2y

(3x + 12)/2 < y

(3/2)x + 6 < y

Now, we just need to graph the line y = (3/2)x + 6 with a dashed line (because the points on the line are not solutions).

And then we need to shade the region above the line.

The graph of the solution set can be seen below.

If you want to learn more about inequalities:

brainly.com/question/18881247

#SPJ1

8 0
2 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
2 years ago
Help please urgent thanks
Alex

Answer:

The answer is 2/10 and 2/10

(A)

8 0
3 years ago
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