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Over [174]
3 years ago
14

What is the elapsed time from 6:45 am to 3:28 pm

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0


6:45a to 7:45  = 1 hour

7:45 to 8:45  = 2 hours

8:45 to 9:45  = 3 hours

9:45 to 10:45 =  4 hours

10:45 to 11:45  = 5 hours

11:45 to 12:45  = 6 hours

12:45 to 1:45  =  7 hours

1:45 to 2:45  = 8 hours

2:45 to 3:00  = 8 hours and 15 minutes

then just add the 28 minutes to the 15 minutes

28 + 15 = 43

6:45a to 3:28p = 8 hours and 43 minutes.

Hope this helps.

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Solve 5x = 2 written a afrction inits simplest form
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Answer:

x = 2/5

General Formulas and Concepts:

Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Write equation</u>

5x = 2

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Divide both sides by 5:          x = 2/5

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution</em>.

  1. Substitute:                    5(2/5) = 2
  2. Multiply:                        10/5 = 2
  3. Divide:                           2 = 2
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3 years ago
Point V is located at -16. Points W and X are each 7 units away from Point V. Where are W and X located?
nasty-shy [4]

Answer:

Location of W is - 23, location of X is - 9.

Step-by-step explanation:

location of V = - 16

Points W and X are each 7 units away from Point V.

Let the W is at left of V and X is right of V.

location of W = -16 - 7 = - 23

location of X = - 16 + 7 = - 9

5 0
3 years ago
A formula for the perimeter of a rectangle is P=2(l+w), where P is the perimeter, l is the length, and w is the width.
NNADVOKAT [17]
1408 because you need to multiply it to get the perimeter
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What is the average size of a highschool diploma?
OlgaM077 [116]
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3 years ago
The graph shows the feasible region for the system with constraints:
Dimas [21]

Answer:

The vertices feasible region are (0 , 15) , (10 , 15) , (20 , 5)

The minimum value of the objective function C is 125

Step-by-step explanation:

* Lets look to the graph to answer the question

- There are 3 inequalities

# y ≤ 15 represented by horizontal line (purple line) and cut the

  y-axis at point (0 , 15)

# x + y ≤ 25 represented by a line (green line) and intersected the

  x-axis at point (25 , 0) and the y- axis at point (0 , 25)

# x + 2y ≥ 30 represented by a line (blue line) and intersected the

  x-axis at point (30 , 0) and the y-axis at point (0 , 15)

- The three lines intersect each other in three points

# The blue and purple lines intersected in point (0 , 15)

# The green and the purple lines intersected in point (10 , 15)

# The green and the blue lines intersected in point (20 , 5)

- The three lines bounded the feasible region

∴ The vertices feasible region are (0 , 15) , (10 , 15) , (20 , 5)

- To find the minimum value of the objective function C = 4x + 9y,

  substitute the three vertices of the feasible region in C and chose

  the least answer

∵ C = 4x + 9y

- Use point (0 , 15)

∴ C = 4(0) + 9(15) = 0 + 135 = 135

- Use point (10 , 15)

∴ C = 4(10) + 9(15) = 40 + 135 = 175

- Use point (20 , 5)

∴ C = 4(40) + 9(5) = 80 + 45 = 125

- From all answers the least value is 125

∴ The minimum value of the objective function C is 125

6 0
3 years ago
Read 2 more answers
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