Answer:
B. control group.
Explanation:
In the given experiment there two <em>groups of participants:</em> the <em>experimental group</em> - students who are consistently given excellent grades in math by their teachers, and the <em>control group</em> - students who are consistently given average scores. The control group is not under influence of the factor of consistently high grades (independent variable), impact of which on self esteem Noelle is testing. Here, the control group is used as a benchmark to <u>measure the effect of the independent variable under investigation</u>.
The answer is B. The circular model illustrate the flow of income and expenditure, and expresses how change by with consumers or producer can influence the other. If consumers were spending less, then producers would lower their production to match the consumer demand for that good or service.
Answer:
0.14007 ; 0.71986
Explanation:
Given that :
Justification :
Mean = np ≥ 10
(1 - np) ≥ 10
n = sample size ; p = 0.15
q 1 - 0.15 = 0.85
np = 1500 * 0.15 = 225 > 10
nq = 1500 * 0.85 = 1275 > 10
Hence, the Justification
P(p" > 0.16)
P(Z > (p" - p) /sqrt(p(q) /n))
P(Z > (0.16- 0.15) /sqrt(0.15(0.85) /1500))
P(Z > 0.01 / 0.0092195)
P(Z > 1.08) = 0.14007
P(0.14 < p < 0.16)
P(Z (0.14- 0.15) /sqrt(0.15(0.85) /1500)) < Z < (0.16 - 0.15) /sqrt(0.15(0.85) /1500))
P(Z <-0.01 / 0.0092195) - 0.01 / 0.0092195)
P(Z < 1.08) - P(Z < - 1.08)
Using the Z probability m calculator :
0.85993 - 0.14007
= 0.71986
= 0.72208
Answer:
166.67%
Explanation:
The computation of the percentage increase in grain production for the period 1950-1955 is shown below:
= (Year 1995 grain production - Year 1950 grain production) ÷ ( Year 1950 grain production)
= (1,600 million tons - 600 million tons) ÷ (600 million tons)
= 1,000 million tons ÷ 600 million tons
= 166.67%
Hence the increase in percentage is 166.67%