Answer:
The mixed number for the amount of cupcakes mark ate is 1 1/6
Step-by-step explanation:
On his birthday mark ate 2/3 of a chocolate cupcake 1/4 of a red velvet cupcake and 1/2 of a vanilla cupcake. How many total cupcakes did mark eat on his birthday?
What is the mixed number for the amount of cupcakes mark ate?
This is solved as:
2/3 of a chocolate cupcake + 1/4 of a red velvet cupcake + 1/2 of a vanilla cupcake.
2/3 + 1/4 + 1/2
The Lowest Common Denominator is 12
8 + 2 + 4/12
= 14/12
= 7/6
= 1 1/6
9514 1404 393
Answer:
t = 1 1/7 ≈ 1.1429 seconds
Step-by-step explanation:
Filling in the given height, we can solve for t:
640 = -490t^2 +1120t
49t^2 -112t +64 = 0 . . . . . divide by 10, put in standard form
(7t -8)^2 = 0
t = 8/7 . . . . . . . the value of t that makes the factor(s) zero
The model rocket will reach its maximum height of 640 cm after 1 1/7 seconds.
Mean: 22
Median: 21
I hope this helps
Answer:
![d=1.28\times 10^{-6}\ g/cm^3](https://tex.z-dn.net/?f=d%3D1.28%5Ctimes%2010%5E%7B-6%7D%5C%20g%2Fcm%5E3)
Step-by-step explanation:
The mass of a bag of sugar, m = 1 kg = 0.001 g
Length of bag, l = 9.2 cm
Width of bag, b = 6 cm
Height of the bag, h = 14.1 cm
We need to find the density of the sugar bag.
Density = mass/volume
So,
![d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7B0.001%5C%20g%7D%7B9.2%5Ctimes%206%5Ctimes%2014.1%5C%20cm%5E3%7D%5C%5C%5C%5Cd%3D1.28%5Ctimes%2010%5E%7B-6%7D%5C%20g%2Fcm%5E3)
So, the density of the bag is
.