Answer:
option 4.
16 square units
Step-by-step explanation:
as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.
P = (2 , 4)
S = (4 , 2)
we have to subtract the values of p from s
PS = (4 - 2 , 2 - 4)
PS = (2 , -2)
by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2
h: hypotenuse
c1: leg 1
c2: leg 2
PS^2 = 2^2 + -2^2
PS = √ 4 + 4
PS = √8
PS = 2√2
S = (4 , 2)
R = (8 , 6)
SR = (8-4 , 6-2)
SR = (4 , 4)
by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2
h: hypotenuse
c1: leg 1
c2: leg 2
SR^2 = 4^2 + 4^2
SR = √ (16 + 16)
SR = √32
SR = 4√2
having the values of 2 of its sides we multiply them and obtain their area
PS * RS = Area
2√2 * 4√2 =
16
The answer will be d i believe
We will verify each options
option-A:
we can factor it
so, this is not irrational.........Answer
option-B:
Since, it can not be factored
so, this is irrational.........................Answer
option-C:
we can factor it
so, this is not irrational.........Answer
option-D:
we can factor it
so, this is not irrational.........Answer
I need help Over the next two days, Benton Employment Agency is interviewing clients who
wish to find jobs. On the first day, the agency plans to interview clients in groups
of 6. On the second day, the agency will interview clients in groups of 8. If the
employment agency will interview the same number of clients on each day, what
is the smallest number of clients that could be interviewed each day?
(x -2)(x - 3)
x(x - 3) - 2(x - 3)
x^2 - 3x - 2x + 6
x^2 - 5x + 6 <===
I dont know what cherise did, but this is the correct way
