What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x2+3 ?

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defon

3 years ago

12

What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x2+3 ?

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Mathematics

2 answers:

Nonamiya [84] · Answer 1 · 2022-03-09T02:57:46+03:00

Nonamiya [84]3 years ago

7 0

<span>Perpendicular lines' slopes are reciprocals of one another. So we know the perpendicular line will have a slope of 1/2. Then we can use our points to find the rest. 8=1/2(1)+b 8=0.5+b 7.5=b y=2x+b</span>

Marta_Voda [28] · Answer 2 · 2022-03-09T04:21:58+03:00

Marta_Voda [28]3 years ago

7 0

After adding everything together you should get y=-2x+10