What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x2+3 ?
2 answers:
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You forgot to mention the graph.
So, I make the graph of both given functions and you will compare your graph with them.
First, y= -x-1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,-1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.
Second, y= x+1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.
So, I make the graph of both given functions and you will compare your graph with them.
First, y= -x-1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,-1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.
Second, y= x+1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.